Drag the tiles to the correct boxes to complete the pairs.

Complete function tables part 2 please help i will mark as brainlyst

Vlad1618 [11]

h

0

2

4

6

1 = 1/2(0) + 1

2 = 1/2(2) + 1

3 = 1/2(4) + 1

4 = 1/2(6) + 1

hope this helps!

6 0

3 years ago

There are 95 candies in the dish.19 of the candies are chocolate. What percent of the candies are left

r-ruslan [8.4K]

Answer:

80%

Step-by-step explanation:

20% of the candies are chocolate, leaving the rest of the 80%

4 0

3 years ago

Maya runs a farm stand that sells raspberries and blueberries. Each pound of raspberries sells for $1 and each pound of blueberr

aniked [119]

30 pounds of raspberries and 50 pounds of blueberries are sold

Solution:

Let "a" be the pounds of raspberries sold

Let "b" be the pounds of blueberries sold

Cost per pound of raspberry = $ 1

Cost per pound of blue berry = $ 3.25

Maya made $192.50 from selling a total of 80 pounds of raspberries and blueberries

Therefore,

a + b = 80

a = 80 - b ------- eqn 1

Maya made $192.50. Therefore, frame a equation as:

pounds of raspberries sold x Cost per pound of raspberry + pounds of blueberries sold x Cost per pound of blue berry = 192.50

$a \times 1 + b \times 3.25 = 192.50$

a + 3.25b = 192.50 ------ eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

80 - b + 3.25b = 192.50

2.25b = 192.50 - 80

2.25b = 112.5

Divide both sides by 2.25

b = 50

Substitute b = 50 in eqn 1

a = 80 - 50

a = 30

Thus 30 pounds of raspberries and 50 pounds of blueberries are sold

3 0

3 years ago

a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.

Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

$A_x=50cos(89.75)$ so