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elixir [45]
2 years ago
8

What is an equation of a line that passes through (0,3) and (2,4)

Mathematics
1 answer:
Tju [1.3M]2 years ago
6 0

Answer:

y=1/2x+3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(4-3)/(2-0)

m=1/2

y-y1=m(x-x1)

y-3=1/2(x-0)

y=1/2(x)+3

y=1/2x+3

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Money is invested into an account earning 4.25% interest compounded annually. If the accumulated value after 18 years will be $2
Sergio039 [100]
P=25,000÷(1+0.0425)^(18)
P=11,818.73
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The temperature at 6:00 pm was 24°. At midnight the temperature 36° lower than 6:00pm . What was the temp at midnight?
horrorfan [7]

Answer:

-12°

Step-by-step explanation:

Man... I just did 36 minus 24, and since it says 36° lower I decided it was -12 degrees (24 - 36 is more accurate but I find it easier just to do it the other way)

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Shaylee has 77 pennies. She will trade in the pennies to get nickels.
Ghella [55]
0.77 / 0.05 = 15.4 ...so we know it is 15 nickels
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6 0
3 years ago
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I need help with 6,7,8,9,10 please
Anna [14]

Can you take a picture of your whole worksheet? only the front page

7 0
3 years ago
Use the box plots comparing the number of male puppies and number of female puppies attending doggy daycare each day for a month
dalvyx [7]
  1. The IQR for the males' data is 25.
  2. The difference between the median of the males' data and the female's data is 14.
  3. The distribution of the males' data is skewed to the right and the median would be a better measure of the center. The distribution of the female's data is normal and the mean would be a better measure of the center.
  4. A reason for the outlier is that the number of dogs needing care increased.

<h3>What is the interquartile range?</h3>

The interquartile range for the males data is the difference between the third quartile and the first quartile.

IQR = third quartile - first quartile

25 - 0 = 25

Median = 20 - 6 = 14

An outlier is a number that is way smaller or way larger than that of other numbers in a data set.

To learn more about outliers, please check: brainly.com/question/27197311

#SPJ1

7 0
1 year ago
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