Suppose that some value, c, is a point of a local minimum point.
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:
As h approaches 0 from the positive side, then:
Thus, f'(c) = 0
Answer:
AB = 10
Step-by-step explanation:
Use the distance formula: √(12 - 18)^2 + (1 - 9)^2
√36 + 64
10
Answer:
Multiplication
Step-by-step explanation:
I believe 2x2 would have a sum of 4.
Answer:
5y2 + 4y - 12 + 6x
Step-by-step explanation:
3y2 + 2y2 + 8y - 12 + 6x