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2 years ago

The sum of 2 numbers is 28. One number is 5 less than twice the other number. What are the numbers?

Mathematics

1 answer:

suter [353]2 years ago

6 0

28 = x + (2x - 5)
28 = 3x - 5
+5 +5
33 = 3x
/3 /3
11 = x

On number is 11, the other is 17.

Check:
11(2)=22-5=17

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A scuba diver dove 40 feet below the surface. He swam up 12 feet to see a unique fish. He followed the fish down 8 feet. Then he

Ber [7]

Answer: 9 feet below the surface.

Step-by-step explanation:

The scuba diver starts 40 ft below the surface. We can represent the position of the scuba diver as:

Position = -40ft

Where the negative sign is because it is below the surface of the water, so

"He swam up 12 feet to see a unique fish."

Now we need to add 12ft

Then his new position is:

Position = -40ft + 12 ft = -28ft

"He followed the fish down 8 feet.

Now we need to subtract 8ft

His new position is:

Position = -28ft - 8 ft = -36 ft

"Then he followed the fish up 27 feet."

Now we add another 27 ft.

The final position will be:

Position = -36ft + 27ft = -9ft

Then the final position of the scuba diver is -9ft, that means that he is 9 feet below the surface.

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2 years ago

Using Parallel Lines Find m 1 and m 2. Explain your reasoning.

Molodets [167]

i don't know if there is a graph for this problem, but m1 should always equal m2

if m1 and m2 are parallel, one line that is perpendicular to m1 is always perpendicular to m2, and the slopes of m1 and m2 are equal and their lines should never intersect

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3 years ago

Use cylindrical coordinates to evaluate the triple integral ∭ where E is the solid bounded by the circular paraboloid z = 9 - 16

4vir4ik [10]

Answer:

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

Step-by-step explanation:

The Cylindrical coordinates are:

x = rcosθ, y = rsinθ and z = z

From the question, on the xy-plane;

$9 -16 (x^2 + y^2) = 0 \\ \\ 16 (x^2 + y^2) = 9 \\ \\ x^2+y^2 = \dfrac{9}{16}$

$x^2+y^2 = (\dfrac{3}{4})^2$

where:

0 ≤ r ≤ $\dfrac{3}{4}$ and 0 ≤ θ ≤ 2π

∴

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} \int ^{9-16r^2}_{0} \ r \times rdzdrd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 z|^{z= 9-16r^2}_{z=0} \ \ \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 ( 9-16r^2}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} ( 9r^2-16r^4}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( \dfrac{9r^3}{3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3r^3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) d \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) \theta |^{2 \pi}_{0}$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{64}}-\dfrac{243}{320}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{160}})2 \pi$

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

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lukranit [14]

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Step-by-step explanation:

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