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alekssr [168]
3 years ago
12

At which vertex is the objective function C=3x-4y minimized

Mathematics
1 answer:
Oliga [24]3 years ago
3 0

Options

(A) (9,0) (B) (-2,20) (C) (-5,2) (D) (0,-9)

Answer:

(B) (-2,20)

Step-by-step explanation:

Given the objective function, C=3x-4y

The vertex at which C is minimized will be the point (x,y) at which the expression gives the lowest value.

<u>Option A </u>

At (9,0), x=9, y=0

C=3(9)-4(0)=27-0

C=27

<u>Option B </u>

At (-2,20), x=-2, y=20

C=3(-2)-4(20)=-6-80

C=-86

<u>Option C</u>

At (-5,2), x=-5, y=2

C=3(-5)-4(2)=-15-8

C=-23

<u>Option D </u>

At (0,-9), x=0, y=-9

C=3(0)-4(-9)=0+36

C=36

The lowest value of C is -86. This occurs at the vertex (-2,20).

Therefore, the objective function C=3x-4y is minimized at (-2,20).

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If the x-intercepts are x = -1 and x = 1, then originally the factors were (x + 1) and (x - 1).  Again, set each of those equal to 0 and solve for x (THE X-INTERCEPT EXISTS WHERE Y = 0!)

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