Let A be some subset of a universal set U. The "complement of A" is the set of elements in U that do not belong to A.
For example, if U is the set of all integers {..., -2, -1, 0, 1, 2, ...} and A is the set of all positive integers {1, 2, 3, ...}, then the complement of A is the set {..., -2, -1, 0}.
Notice that the union of A and its complement make up the universal set U.
In this case,
U = {1, 2, 3, 6, 10, 13, 14, 16, 17}
The set {3, 10, 16} is a subset of U, since all three of its elements belong to U.
Then the complement of this set is all the elements of U that aren't in this set:
{1, 2, 6, 13, 14, 17}
Answer:
x = 3
Step-by-step explanation:
Given the 2 equations
x + y = 3 → (1)
2x - y = 6 → (2)
Adding the 2 equations term by term eliminates the y- term, that is
3x = 9 ( divide both sides by 3 )
x = 3
The answer to these blanks are :
1. 6 (m)
2. 1 (s)
3. 0 (m)
4. 4 (s)
Answer:
Step-by-step explanation:
(X+4)1999=1
Open the bracket by multiplying 1999 by the values in the bracket
1999x + 7996 = 1
Collect like terms
1999x = 1-7996
1999x = -7995
Divide both sides by 1999
X = -3.99
