Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer: 4
Step-by-step explanation:
Answer:
84 degrees
Step-by-step explanation:
132+54 = 186 degrees
186+90 = 276 degrees
as this is around a point it totals to 360 degrees
360 degrees - 276 degrees = 84 degrees
hope this helps
Answer:
1.5225 gumbo squared
Step-by-step explanation:
First we know that 1 gumbo is equal to 8.5 lollygams.
To know the number of gumbo squared in 110 lollygam squared, we need to know the relation between 1 gumbo squared and 1 lollygam squared, and we do that making the square of our relation between gumbo and lollygams:
1 gumbo -> 8.5 lollygams
1 gumbo squared -> (8.5)^2 lollygams squared = 72.25 lollygams squared
Now, to know the number of gumbo squared in 110 lollygam squared, we just need to divide 110 by 72.25:
1 gumbo squared -> 72.25 lollygams squared
x gumbo squared -> 110 lollygams squared
x = 110/72.25 = 1.5225 gumbo squared
