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alexgriva [62]
3 years ago
13

A listing posted by a restaurant chain gives, for each of the sandwiches it sells, the types of fillings for the sandwiches, num

ber of calories, and carbohydrate content in grams. The data might be helpful to assess the nutritional value of the various sandwiches.
Who was​ measured?

a. The food at the restaurant chain
b. The restaurant​ chain's sandwichessandwiches
c. The restaurant chain
d. This information is not given.
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:

NB: There are two possible answer to this question, depending on the correctness of the question asked.

<em>In the case where the question 'who was measured ?' is the correct question</em>, then the the <em>correct answer will be D</em>, since <em>the word 'who' is an interrogative pronoun and a relative pronoun, used chiefly to refer to </em><u><em>humans</em></u><em>. </em>In that case, no one was actually measure or <em>we simply state that the 'information is not given'.</em>

<em>But if assume that the question to the answer is 'what was measured ?' and not 'who was measured ?',</em> In this case, <em>only the data gotten from the measurement of properties of the fillings in the sandwiches served by the restaurant chain was given</em>, and option B is the correct answer.

<em></em>

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If Upper X overbar equals 62​, Upper S equals 8​, and n equals 36​, and assuming that the population is normally​ distributed, c
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Answer:

The 99% confidence interval would be given by (58.373;65.627)    

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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\bar X=62 represent the sample mean

\mu population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size  

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=36-1=35

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that t_{\alpha/2}=2.72

Now we have everything in order to replace into formula (1):

62-2.72\frac{8}{\sqrt{36}}=58.373    

62+2.72\frac{8}{\sqrt{36}}=65.627    

So on this case the 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

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