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3 years ago

Can someone explain how to do #7?

Mathematics

2 answers:

FrozenT [24]3 years ago

5 0

You have to take out the "|"
8x-1 ≤ 2x+11
8x-2x ≤ 11+1
6x ≤ 12
X ≤ 12/6
X ≤ 2

Oksanka [162]3 years ago

5 0

Collect the like terms
8x-2x is greater than equals to 11+1
10x<_12 then divide both sides by 10
x<_0.83

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Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{x = - 10}}}}}$

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Hope I helped!

Best regards!!

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