Answer:
Properties of operations help a lot in solving problems related to integers and rational numbers.
<u>Step-by-step explanation:</u>
There are four properties of operations in math. These properties are applicable in case of addition and multipication but not in case of division and subtraction.
These properties are used to solve problems involving rational numbers as well as integers.These properties are associative,commutative, distributive and identity.
commutative property is A+B=B+A
⇒5+4=4+5
and A*B=B*A
⇒5*4=4*5
associative property ( 32+14)+7= 32+(14+7)
( 8*9)*7= 8*(9*7)
Identity property is 35+0= 35
1*58=58
distributive property is 15*21
⇒ 15*(20+1)
⇒15*20+15*1
15*21
⇒ 15*(22-1)
⇒15*22-15*1
The given translation adds (-5, -4) to the coordinates of the given point.
(-5, 10) + (-5, -4) = (-5-5, 10-4) = (-10, 6)
The value of p that makes the given equation true is equal to: B. p = -5
<u>Given the following equation:</u>
To find a value of p that makes the given equation true:
In this exercise, you're required to determine a value of p that satisfies the given equation true such that when substituted into the equation, it has a true result or outcome.
Rearranging the equation by collecting like terms, we have:
p = -5
Find more information: brainly.com/question/3600420
B and e if you plug it in desmos it gives you direct coordinates
Answer:
t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))
Step-by-step explanation:
Solve for t:
z = (h t^2)/2 + t q_1
z = (h t^2)/2 + t q_1 is equivalent to (h t^2)/2 + t q_1 = z:
(h t^2)/2 + t q_1 = z
Divide both sides by h/2:
t^2 + (2 t q_1)/h = (2 z)/h
Add q_1^2/h^2 to both sides:
t^2 + (2 t q_1)/h + q_1^2/h^2 = (2 z)/h + q_1^2/h^2
Write the left hand side as a square:
(t + q_1/h)^2 = (2 z)/h + q_1^2/h^2
Take the square root of both sides:
t + q_1/h = sqrt((2 z)/h + q_1^2/h^2) or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)
Subtract q_1/h from both sides:
t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)
Subtract q_1/h from both sides:
Answer: t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))
