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Amiraneli [1.4K]
2 years ago
7

Solve for t. Express your answer in simplest and exact form.

Mathematics
1 answer:
Masteriza [31]2 years ago
8 0

Answer:

t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))

Step-by-step explanation:

Solve for t:

z = (h t^2)/2 + t q_1

z = (h t^2)/2 + t q_1 is equivalent to (h t^2)/2 + t q_1 = z:

(h t^2)/2 + t q_1 = z

Divide both sides by h/2:

t^2 + (2 t q_1)/h = (2 z)/h

Add q_1^2/h^2 to both sides:

t^2 + (2 t q_1)/h + q_1^2/h^2 = (2 z)/h + q_1^2/h^2

Write the left hand side as a square:

(t + q_1/h)^2 = (2 z)/h + q_1^2/h^2

Take the square root of both sides:

t + q_1/h = sqrt((2 z)/h + q_1^2/h^2) or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)

Subtract q_1/h from both sides:

t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)

Subtract q_1/h from both sides:

Answer: t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))

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They must buy 501 pounds of produce for the membership to be worth it.

Step-by-step explanation:

You can solve this question by first finding the difference between $0.10 and $0.25.

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You then divide 75 by 0.15 to find the extra weight it would take for the produce to equal $75. You should get 500 pounds.

At 500 pounds, the price would be equal if you had a membership or not.

You then must add 1 pound to make it more favorable to have the membership.

At 501 pounds the person with the membership would pay $125.10 and the person without the membership would pay $125.25

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3 years ago
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Swimming Pool On a certain hot​ summer's day, 253 people used the public swimming pool. The daily prices are $ 1.50 for children
e-lub [12.9K]

Answer:

Therefore 164 children and 89 adults swam at the public pool that day.

Step-by-step explanation:

Given that,

253 people used the public swimming pool.

The daily prices for children are  $1.50 and for adults are $2.25.

Let the number of children be x.

Then number of adult is (253-x)

The total money collect on that day is  =\$[(1.50\times x)+2.25(253-x)]

                                                               =\$[1.50x+569.25-2.25x]

                                                                =\$[569.25-0.75x]

According to the problem,

569.25-0.75x=446.25

\Rightarrow  -0.75 x=446.25-569.25

\Rightarrow  -0.75 x=-123

\Rightarrow x=\frac{123}{0.75}

\Rightarrow  x=164

Therefore 164 children and (253-164)=89 adults swam at the public pool that day.

8 0
3 years ago
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