1t + 3g + 0e = x
t=6
g=3
e=1
1(6) + 3(3) + 0(1) = x
6 + 9 + 0 = x
15 = x
Answer:
a=3
b=24
Step-by-step explanation:
If is a factor of , then the factors of must also be factors of .
So what are the factors of ? Well the cool thing here is the coefficient of is .
The zeros of are therefore x=-4 and x=3. We know those are zeros of by the factor theorem.
So x=-4 and x=3 are also zeros of because we were told that was a factor of it.
This means that when we plug in -4, the result will be 0. It also means when we plug in 3, the result will be 0.
Let's do that.
Equation 1.
Equation 2.
Let's simplify Equation 1 a little bit:
Let's simplify Equation 2 a little bit:
So we have a system of equations to solve:
16a-b=24
9a-b=3
---------- This is setup for elimination because the b's are the same. Let's subtract the equations.
16a-b=24
9a-b= 3
------------------Subtracting now!
7a =21
Divide both sides by 7:
a =3
Now use one the equations with a=3 to find b.
How about 9a-b=3 with a=3.
So plug in 3 for a.
9a-b=3
9(3)-b=3
27-b=3
Subtract 27 on both sides:
-b=-24
Multiply both sides by -1:
b=24
So a=3 and b=24
Answer:
1.59
Step-by-step explanation:
12*5 = 60
60/37.80 = 1.59
a) is conservative if it is the gradient field for some scalar function . This would require
Integrating both sides of the first equation with respect to yields
Differentiate with respect to :
Differentiate with respect to :
We want to be independent of and ; we can make them both disappear by picking .
b) This is the so-called triple product, which has the property
Computing the determinant is easy with a cofactor expansion along the first column:
c) Let
Compute the partial derivatives and evaluate them at :
Then the tangent plane to at (1, 1, 1) has equation
d) In polar coordinates, is the set
Then the integral evaluates to
e) By the chain rule,
Eliminating the parameter, we find
so that when .
Compute derivatives:
Then at the point (1, 1), the derivative we want is