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adelina 88 [10]
2 years ago
12

F(x)=sqrt x+2; g(x)=sqrt 8x-6. FInd f(g(x))

Mathematics
1 answer:
zhenek [66]2 years ago
7 0

Hello!

This question is an example of composition of functions. It is using range values of some given function as domain values of some other given function to find new range values. Remember that the domain of the composite function will be the same as the domain of the first function.

Given f(g(x)), for f = \sqrt{x+2}, substitute x with g(x) = \sqrt{8x-6}.

Therefore, f(g(x))= \sqrt{\sqrt{8x-6} +2}.

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Answer:

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Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( x_{1}, y_{1} ) & ( x_{2}, y_{2} )-

 y - y_{1}  = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }   ( x - x_{1}  )

i.e. <em> y - 7= \frac{- 1 - 7}{ -3-1}  ( x- 1)</em>

<em>       y - 7 =  \frac{- 8}{- 4} ( x -1)</em>

<em>       y - 7 =  2 ( x - 1) </em>

<em>       y - 7  =   2  x - 2</em>

<em>       2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1)  is 2 x - y  + 5 = 0.

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