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adelina 88 [10]
3 years ago
12

F(x)=sqrt x+2; g(x)=sqrt 8x-6. FInd f(g(x))

Mathematics
1 answer:
zhenek [66]3 years ago
7 0

Hello!

This question is an example of composition of functions. It is using range values of some given function as domain values of some other given function to find new range values. Remember that the domain of the composite function will be the same as the domain of the first function.

Given f(g(x)), for f = \sqrt{x+2}, substitute x with g(x) = \sqrt{8x-6}.

Therefore, f(g(x))= \sqrt{\sqrt{8x-6} +2}.

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Given: ∆ABC, AC = 12,<br> AB = BC = 10<br> Find: m∠A, m∠C, m∠B
4vir4ik [10]

Answer:

  • m∠A ≈ 53.13°
  • m∠B ≈ 73.74°
  • m∠C ≈ 53.13°

Step-by-step explanation:

An altitude to AC bisects it and creates two congruent right triangles. This lets you find ∠A = ∠C = arccos(6/10) ≈ 53.13°.

Since the sum of angles of a triangle is 180°, ∠B is the supplement of twice this angle, so is about 73.74°.

  m∠A = m∠C ≈ 53.13°

  m∠B ≈ 73.74°

_____

The mnemonic SOH CAH TOA reminds you of the relation between the adjacent side, hypotenuse, and trig function of an angle:

  Cos = Adjacent/Hypotenuse

If the altitude from B bisects AC at X, triangle AXB is a right triangle with side AX adjacent to the angle A, and side AB as the hypotenuse. AX is half of AC, so has length 12/2 = 6, telling you the cosine of angle A is AX/AB = 6/10.

A diagram does not have to be sophisticated to be useful.

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Answer:

One

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The solution to the system is (1, 5)

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2 years ago
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