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e-lub [12.9K]
4 years ago
7

Hey i need help like now !!

Mathematics
1 answer:
koban [17]4 years ago
8 0

Answer:

It would be 12

Step-by-step explanation:

It would be 12 because 12 students and 17 students enjoy something else and the least will be correct

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If a towns population currently at 50,000 experiences 5% growth every 10 years, what will its population be in 25 years
disa [49]

Answer:

56503

Step-by-step explanation:

this grows exponentialy so at the start it would be 50,000 growing by 5% every ten years. but since there is only 2 ten years in 25 years we must cut the percent in half making 2.5%

Step 1

(50,000×5%)+50,000= 52500

Step 2

(52500×5%)+52500= 55125

step 3

(55125×2.5%) +55125= 56503

5 0
2 years ago
A work shift for an employee at a restaurant consists of 12 hours. What fraction of the​ employee's work shift is represented by
Vaselesa [24]

Answer:

4/12 or 1/3

Step-by-step explanation:

there is a fraction of 4 hours in the 12 hours, so 4/12.

That can be simplified to 1/3.

6 0
3 years ago
2) 45+ 17 = 62<br><br> 3) X + 5/6 = 7/16<br><br> 4) Y + 1/7 = 5/8
Montano1993 [528]

9514 1404 393

Answer:

  2) true

  3) X = -19/48

  4) Y = 27/56

Step-by-step explanation:

3) Subtract 5/6 from both sides

  X = 7/16 -5/6 = (7·6 -16·5)/(16·6) = (42 -80)/96

  X = -19/48

__

4) Subtract 1/7 from both sides

  Y = 5/8 -1/7 = (5·7 -8·1)/(8·7)

  Y = 27/56

6 0
3 years ago
What is the solution to the equation below log5(2x-3)=2
Komok [63]

Answer:

Step-by-step explanation:

Use the exponential form of this log equation. Rewriting this into exponential form gives us

5^2=2x-3

5-squared is 25, so

25 = 2x - 3 and

22 = 2x so

x = 11

7 0
3 years ago
Solve the initial value problem. dy/dt = 1 + 6/t , t &gt; 0, y = 8 when t = 1
nordsb [41]
\displaystyle\frac{dy}{dt} = 1 + \frac{6}{t}\ \Rightarrow\ dy = \left( 1 + \frac{6}{t}\right) dt\ \Rightarrow\int 1\, dy = \int \left( 1 + \frac{6}{t}\right) dt \ \Rightarrow \\ \\&#10;y = t + 6\ln|t| + C. \text{ But $t\ \textgreater \ 0$ so }y = t + 6\ln t + C. \\ \\ &#10;y(1) = 8\ \Rightarrow\ 8 = 1 + 6 \ln 1 + C \ \Rightarrow\ C = 7 \text{ so } \\ \\&#10;y(t) = t + 6\ln t + 7
5 0
3 years ago
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