Take the derivitive
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)
make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment
max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)
so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?
Step 1: List the numbers in order (Least - Greatest): 2, 2, 5, 5, 19, 19, 25, 25, 28
Step 2: Find the middle number: <span>2, 2, 5, 5, 19, 19, 25, 25, 28
Answer: 19
(Information for further questions): If there are 2 middle numbers, average them. (Add them up and divide by 2)</span>
For this case we have a function of the form
Where:
We must find the value of the function when the variable x is -5.
Then, substituting,
We have that by sign law
Answer:
Your answer is 29, hope I helped!!