1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svetlanka [38]
3 years ago
5

Choose the best translation of the English phrase.

Mathematics
2 answers:
yaroslaw [1]3 years ago
6 0

Answer:

The answer is d


Step-by-step explanation:


Kobotan [32]3 years ago
5 0
A because we know that s stands for square feet right and it is 100 square feet therefore your answer is A
You might be interested in
Graycie and her 6 friends are using 293 beads to make bracelets. They share the beads evenly but some were left over. How many b
FrozenT [24]

Answer:

47

Step-by-step explanation:

3 0
3 years ago
If C = 1+ p2 + 3p and B = 2p + 6p, find an expression that equals 2C – – B in
drek231 [11]

Answer:

2p² + 14p + 2

Step-by-step explanation:

Given that;

C= 1+p²+3p

B=2p+6p

The expression that equals to : 2C - -B will be;

2{1+p²+3p} - {-2p-6p}

2+2p²+6p + 2p + 6p

2p² + 6p +2p +6p +2

2p² + 14p + 2

4 0
3 years ago
Explain why parallelograms are always quadrilaterals but quadrilaterals are sometimes parallelograms
Gnoma [55]
Im sure this website will help answer.com
7 0
3 years ago
What are the solutions of the inequality? -2(3x + 2) ≥ -6x - 4 Question 2 options: all real numbers x ≤ 6 no solution x ≥ 0
Tju [1.3M]

Solution, -2\left(3x+2\right)\ge \:-6x-4\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:True\quad \forall \:x\in \mathbb{R}\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}

Steps:

-2\left(3x+2\right)\ge \:-6x-4

\mathrm{Expand\:}-2\left(3x+2\right),\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac,\\a=-2,\:b=3x,\:c=2,\\-2\cdot \:3x+\left(-2\right)\cdot \:2,\\\mathrm{Apply\:minus-plus\:rules},\\+\left(-a\right)=-a,\\-2\cdot \:3x-2\cdot \:2,\\\mathrm{Simplify}\:-2\cdot \:3x-2\cdot \:2,\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6,\\-6x-2\cdot \:2,\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4,\\-6x-4,\\-6x-4\ge \:-6x-4

\mathrm{Add\:}4\mathrm{\:to\:both\:sides},\\-6x-4+4\ge \:-6x-4+4

\mathrm{Simplify},\\-6x\ge \:-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides},\\-6x+6x\ge \:-6x+6x

\mathrm{Simplify},\\0\ge \:0

\mathrm{Therefore,\:the\:final\:solution\:is},\\True\quad \forall \:x\in \mathbb{R}

Or\:No\:Solution\:x\geq 0


8 0
3 years ago
A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96m long and 74m wide.
Oduvanchick [21]

Answer:

11402.66 m^{2}

Step-by-step explanation:

The width of rectangle is the diameter of the semi-circle part

Area of one semicircle is given by \frac {0.5\pi d^{2}}{4}

Total area of semi circle will be 2\times\frac {0.5\pi d^{2}}{4}

Substituting 74 m for d and \pi as 3.14 we obtain

Total area semi-circle=2\times\frac {0.5*3.14\times 74^{2}}{4}=4298.66 m^{2}

Area of rectangle is given by the product of length and width

Rectangular area=96 m*74 m=7104 m^{2}

Total area of rectangular and semi-circles will be

4298.66 m^{2}+7104 m^{2}=11402.66 m^{2}

Therefore, area of training field is 11402.66 m^{2}

6 0
3 years ago
Other questions:
  • Which one of the following examples represents a repeating decimal?
    5·1 answer
  • (4+2r)3 solve equation please
    7·1 answer
  • I need help ASAP I’ll give brainliest to that person :)
    15·1 answer
  • I need help finding X please
    14·1 answer
  • Please help me with this easy question...
    7·2 answers
  • What is the solution to this equation?
    13·1 answer
  • AB is parallel to ED.
    10·1 answer
  • Look at the coordinate plane. Which quadrant is the point (-3, 2) in?
    7·2 answers
  • What is the length of X?<br> a = 6.4<br> b = 12
    8·1 answer
  • How many full cases and additional items are needed to fulfill the order? 50 8
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!