1/3= 5/15
2/5= 6/15
5/15 + 6/15 = 11/15
15/15 - 11/15 = 4/15
Part C= 4/15
the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
The entire picture is needed to solve. the bottom of the pic is cut off
Answer:
190% of 66= 125.4
rounded to the nearest tenth:130
Answer:
x = -8
Step-by-step explanation:
g(x) = 8x + 2
given: g(x) = 8x + 2 = -62
8x = -62 -2
8x = -64
x = -8
