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Eddi Din [679]
3 years ago
15

If f(x) = 2x - 6 and g(x) = 3x + 9, find (f - g)(x).

Mathematics
2 answers:
nataly862011 [7]3 years ago
8 0

(f-g)(x)=2x-6-(3x+9)=2x-6-3x-9=-x-15

Black_prince [1.1K]3 years ago
4 0

Answer:

The correct option is C.

Step-by-step explanation:

The correct option is C.

We have given:

f(x) = 2x - 6 and g(x) = 3x + 9

Now we have to find (f-g)(x)

(f-g)(x) = f(x)- g(x)

Now subtract g(x) from f(x)

(2x - 6) - (3x + 9)

Open the parenthesis. When we open the parenthesis the signs of second bracket will become negative because there is a negative sign outside the bracket.

(f-g)(x)= 2x-6-3x-9

Now solve the like terms:

(f-g)(x)= -x-15

Thus the correct option is C....

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“on the following checking account record, enter the figures and add or subtract them to keep the running total correct”
oksano4ka [1.4K]

The running total is  $95.27.

There are two types of records, Active and Inactive. There are also two major classifications, Vital and Important.

<h3>Why is record keeping important?</h3>
  • In order to create reliable financial statements, you need good records. These consist of balance sheets and income (profit and loss) statements. These statements might assist you in managing your business and dealing with your bank or creditors.

He opened the account with $299.88. He subsequently wrote many cheques, from which you deduct the sum of 299,88.

He deposited a check, thus 299.88-90.48= 209.40, 209.40 - 65.00= 144.40, and then he added $381.33 to 144.40 to get 525.73.

then you need to deduct more since he wrote more checks.

Consequently, 525.73-54.47=471.26, and 471.26-375.99=95.27, giving him a balance of $95.27.

  • Good Records entail documents comprising recorded data that show the efficacy of the quality management system, independent of the format or feature.

To learn more about record keeping refer to:

brainly.com/question/25132652

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6 0
8 months ago
Read 2 more answers
Becky has sold 22 candy bars for a fundraiser. Her goal is to sell a total of 45 candy bars. How many more cany bars does Becky
LenKa [72]
45 - 22 = 23

c + 22 = 45
23 + 22 = 45

I hoped this answered the question correctly! Have a great day!!:)
5 0
2 years ago
Read 2 more answers
Hey, can you help me out here (please)?
FinnZ [79.3K]
In the x quarts of 2% fat milk, there is 0.02x quarts of fat.
in the y quarts of 4% fat milk there is 0.04y quarts of fat.
together, there is (x+y) quarts of milk, and 0.24 quarts of fat.
the equations are:
x+y=9
0.02x+0.04y=0.24
multiply the first equation with 0.02: 0.02x+0.02y=0.18
subtract this new equation from equaition 2 to eliminate x:
0.04y-0.02y=0.24-0.18
0.02y=0.06
y=3
x=9-3=6
x is twice as much as y.
He used twice as much as the 2% fat milk than the 4% fat milk. 
so the first choice is the correct answer. 

8 0
2 years ago
Suppose that the functions p and q are defined as follows.
inessss [21]

The most appropriate choice for function can be given by

qop(3) =  \sqrt{15}+1

poq(3) =  2\sqrt{3} + 10

What is function?

A function from A to B is a rule that maps to each element of A a unique element of B.

A is called the domain of the function and B is called the co domain of the function.

We can do addition, subtraction, multiplication, division and composition on functions.

Let f and g be two functions

fog(x) = f(g(x)) and gof(x) = g(f(x))

This is known as composition of function.

Here,

p(x) = x^2 + 6\\q(x) = \sqrt{x} +1

qop(x) = q(p(x))

          =q(x^2+6)

          = \sqrt{x^2+6}+1

qop(3) = \sqrt{3^2+6}+1

          = \sqrt{15}+1

poq(x) = p(q(x))

          = p(\sqrt{x}+1)

          = (\sqrt{x}+1)^2+6

          = x + 1 + 2\sqrt{x} + 6

          = x + 2\sqrt{x} +7

poq(3) = 3 + 2\sqrt{3}  +7

               2\sqrt{3} + 10

               2\sqrt{3} + 10

To learn more about functions, refer to the link:

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7 0
9 months ago
James wants to compete in the international speed texting competition next year where participants compete on text speed and acc
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A: His texting speed after one month of practice would be 2 1/2 characters per second. (2 + 1/2)

B: His texting speed after two months of practice would be 3 characters per second. (2 1/2 + 1/2)

C: His texting speed after three months of practice would be 3 1/2 characters per second. 3 + 1/2)

D: Algebraic Expression: s = 1/2m + 2

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