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notka56 [123]
4 years ago
15

Write the vertex form of the equation of the parabola which has a vertex of (0, 0) and contains the point (2, –2).

Mathematics
1 answer:
SSSSS [86.1K]4 years ago
5 0
Hello: 
an equation is : f(x) = a(x-0)² +0
the point (2 , -2)in parabola : -2= a(2-0)² +0 
-2=4a
a =-1/2  is the coefficient of the squared expression in the parabola equation
<span>the vertex form is m f(x) = -1/2x²</span>
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Z^m-n (z^m+ z^m+n + z^n)
rusak2 [61]

Answer:Your left hand side evaluates to:

m+(−1)mn+(−1)m+(−1)mnp

and your right hand side evaluates to:

m+(−1)mn+(−1)m+np

After eliminating the common terms:

m+(−1)mn from both sides, we are left with showing:

(−1)m+(−1)mnp=(−1)m+np

If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:

(−1)(−1)mn=(−1)n.

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(−1)(−1)mn=(−1)−n=1(−1)n

Multiplying both sides by (−1)n then yields:

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8 0
3 years ago
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