All categories

3 years ago

Arturo builds a cube that measures 5 in on each side. What is the volume of Arturo's cube?

1 answer:

6 0

We know that

[volume of a cube]=b³
where
b------> is a side length of a cube
for b=5 in
[volume of a cube]=5³--------> 125 in³

the answer is 125 in³

You might be interested in

Ms. D's 4th period geometry class has both freshman and sophomores. There are 27 kids in the class and it has twice as many fres

BARSIC [14]

13.5 freshman well rounded off to 14 freshman

6 0

2 years ago

Olivia has a certain number of pieces of candy that she wants to share evenly with her siblings. She has 2 sisters and a brother

Svetlanka [38]

Probally not sorry hhaahhaa

3 0

3 years ago

Read 2 more answers

a village having a population of 4000, requires 150 litres of water per head per day. it has a tank measuring 20m x 15m x 6m. fo

allochka39001 [22]

The water will last for 3 days

Solution:

Given that, village having a population of 4000, requires 150 litres of water per head per day

Let us first find the volume of tank

The tank measuring 20m x 15m x 6m

Length = 20 m

Breadth = 15 m

Height = 6 m

$volume\ of\ tank = length \times breadth \times height$

$Volume\ of\ tank = 20 \times 15 \times 6 = 1800$

Thus volume of tank is 1800 cubic meter

From given,

Water required per person per day = 150 liters

Therefore, water required for 4000 people per day is:

$\rightarrow 4000 \times 150 = 600000 \text{ liters }$

Convert to meters

$600000 \text{ liters } = 600000 \times \frac{1}{1000}\ m^3\\\\600000 \text{ liters } = 600\ m^3$

How many days will the water of this tank last?

$\text{Number of days water will last } = \frac{\text{volume of tank}}{\text{total water required per day}}$

$\text{Number of days water will last } = \frac{1800}{600} = 3$

Thus the water will last for 3 days

5 0

3 years ago

Linear pairs are___ supplementary. A) always B) sometimes C) never

OverLord2011 [107]

Answer:

always

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

1) 5x-2y=4. 2) 3x-5y=13 x-2y=5 3x+y=9

Natali [406]

$\left\{\begin{array}{ccc}5x-2y=4\\3x+y=9&/\cdot2\end{array}\right\\+\left\{\begin{array}{ccc}5x-2y=4\\6x+2y=18\end{array}\right\\----------\\.\ \ \ \ \ 11x=22\ \ \ \ /:11\\.\ \ \ \ \ \ \ x=2\\\\3\cdot2+y=9\\6+y=9\\y=9-6\\y=3\\\\Answer:x=2;\ y=3$

$\left\{\begin{array}{ccc}3x-5y=13\\x-2y=5\end{array}\right\\\left\{\begin{array}{ccc}3x-5y=13\\x=2y+5\end{array}\right\\\\substitute:\\\\3(2y+5)-5y=13\\6y+15-5y=13\\y=13-15\\y=-2\\\\x=2\cdot(-2)+5=-4+5=1\\\\Answer:x=1;\ y=-2.$

5 0

3 years ago