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Flura [38]
3 years ago
15

4 cm7 cm2 em10 cm9 cm​

Mathematics
1 answer:
Mariana [72]3 years ago
5 0
That’s a pentagon :)
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Find the missing exponent
Hunter-Best [27]

Answer:

-6

Step-by-step explanation:

Because 2×(-6) is - 12

8 0
2 years ago
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HELP NEED URGENT IN NEXT 5 MINS!!!!!! PLEASE HELP
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The linear function is: g = 3n-2. Plug in values from -2 to 4 into n. Like so, G = 3(-2)-2 = g = -8. So, n(x) = -2 and g(y) = -8. And so on, and so on.

Basically, your n values are the x values.
The number you get out of the equation will be your y value.
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2 years ago
The drawing plan for an art studio shows a rectangle that is 19.2 inches by 8 inches. The scale in the plan is 4 in.: 5 ft. Find
Svetradugi [14.3K]
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2 years ago
Identify three solutions of the graph shown. Please help
barxatty [35]
From the graph, we can see that the graph crosses the x-axis at the point (1.5, 0) the graph also passes through point (1, 1) and the graph crosses the y-axis at the point (0, 3).

Therefore, points (1.5, 0), (1, 1) and (0, 3) are some of the solutions of the graph.
5 0
3 years ago
The scatter plot shows a correlation between the years and the rainfall in centimeters in Tennessee.
nataly862011 [7]

Answer:

7

4

Step-by-step explanation:

The <u>actual values</u> are shown on the given graph as <u>blue points</u>.

The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.

From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43).  It appears that the regression line is at y = 50 when x is the year 2000.

⇒ Difference = 50 - 43 = 7 cm

<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.

From inspection of the graph, in the year 2003 the actual rainfall was 44 cm,  shown by point (2003, 40).  It appears that the regression line is at y = 40 when x is the year 2003.

⇒ Difference = 44 - 40 = 4 cm

<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>

3 0
1 year ago
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