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3 years ago

What is -√12+3√3? I need to know.

Mathematics

2 answers:

egoroff_w [7]3 years ago

7 0

-√12 + 3√3

Rewrite √12 as 2√3

-2√3 + 3√3

Just add the numbers before the radical.

-2 + 3 = 1

1√3 = √3

<h3>The simplified form of the provided expression is √3 or 1.73</h3>

Gelneren [198K]3 years ago

4 0

Answer:

√3

Step-by-step explanation:

√12=2√3

-2√3+3√3 = √3

Use calculator to estimate if necessary: 1.7320508075688773

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2 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

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2 years ago

Simplify,write equivalent expressions. 1/6(15a+20b)

lutik1710 [3]

1/6* (15a+20b)
= 1/6* 15a + 1/6* 20b (Distributive property)
= 2.5a + 10/3*b

The final answer is 2.5a+ 10/3b

Hope this helps~

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3 years ago

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In order to play in chess tournaments at the Marshall Club, Malik pays a fee to become a member. In addition, he pays a set rate

Keith_Richards [23]

Answer:

p = 22.50 + 15t

Step-by-step explanation:

For Malik :

Membership fee = m

Rate per tournament = t

After 4 tournaments :

m + 4t = 85 - - - (1)

After 7 tournaments :

m + 7t = 130 - - - (2)

Subtract 2 from 1

4t - 7t = 85 - 130

-3t = - 45

t = 45 / 3

t = 15

Put, t = 15 in (1)

m + 4(15) = 85

m + 60 = 85

m = 85 - 60

m = 25

Massai pays 10% less membership fee than Malik

Hence, Massai's membership fee:

(100 - 10)% * 25

0.9 * 25 = $22.50

Total price, p, Massai will pay to compete in t tournaments ;

Total price = membership fee + (rate per tournament * number of tournaments)

p = 22.50 + 15t

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3 years ago