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Sever21 [200]
3 years ago
10

Figure II is a translation image of Figure 1. Write a rule to describe the translation.

Mathematics
1 answer:
mario62 [17]3 years ago
5 0

Answer:

a translation of (-2,4)

Step-by-step explanation:

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CaHeK987 [17]
The answer too this question is 4
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2 years ago
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A dog starts walking, slows down,
Tomtit [17]

Answer:

You would draw a sloped line leaning to the right, then make it less steep, then draw a flat line.

Explanation:

The steeper slope represents the dog walking at a normal pace, when the line gets a little less steep it means the dog has slowed down, and when it is flat is where ethe dog took a rest.

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

7 0
3 years ago
(a) Let R = {(a,b): a² + 3b <= 12, a, b € z+} be a relation defined on z+)
grin007 [14]

Answer:

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Step-by-step explanation:

The relation R is an equivalence if it is reflexive, symmetric and transitive.

The order to options required to show that R is an equivalence relation are;

((a, b), (a, b)) ∈ R since a·b = b·a

Therefore, R is reflexive

If ((a, b), (c, d)) ∈ R then a·d = b·c, which gives c·b = d·a, then ((c, d), (a, b)) ∈ R

Therefore, R is symmetric

If ((c, d), (e, f)) ∈ R, and ((a, b), (c, d)) ∈ R therefore, c·f = d·e, and a·d = b·c

Multiplying gives, a·f·c·d = b·e·c·d, which gives, a·f = b·e, then ((a, b), (e, f)) ∈R

Therefore R is transitive

From the above proofs, the relation R is reflexive, symmetric, and transitive, therefore, R is an equivalent relation.

Reasons:

Prove that the relation R is reflexive

Reflexive property is a property is the property that a number has a value that it posses (it is equal to itself)

The given relation is ((a, b), (c, d)) ∈ R if and only if a·d = b·c

By multiplication property of equality; a·b = b·a

Therefore;

((a, b), (a, b)) ∈ R

The relation, R, is reflexive.

Prove that the relation, R, is symmetric

Given that if ((a, b), (c, d)) ∈ R then we have, a·d = b·c

Therefore, c·b = d·a implies ((c, d), (a, b)) ∈ R

((a, b), (c, d)) and ((c, d), (a, b)) are symmetric.

Therefore, the relation, R, is symmetric.

Prove that R is transitive

Symbolically, transitive property is as follows; If x = y, and y = z, then x = z

From the given relation, ((a, b), (c, d)) ∈ R, then a·d = b·c

Therefore, ((c, d), (e, f)) ∈ R, then c·f = d·e

By multiplication, a·d × c·f = b·c × d·e

a·d·c·f = b·c·d·e

Therefore;

a·f·c·d = b·e·c·d

a·f = b·e

Which gives;

((a, b), (e, f)) ∈ R, therefore, the relation, R, is transitive.

Therefore;

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Based on a similar question posted online, it is required to rank the given options in the order to show that R is an equivalence relation.

Learn more about equivalent relations here:

brainly.com/question/1503196

4 0
2 years ago
Find the slope of the picture shown
JulijaS [17]

your answer is C 2/3 referring to over to the right 2 times and up 3 times

3 0
2 years ago
If yu were to randomly survey 500 people each from two largest us cities would this be a random study why or why not HELP NEEDED
Valentin [98]

Answer:

If you're timed then I would say,

Yes this is a random study because the problem specifically states that the survey samples were randomly selected from populations.

I think that is the answer! However, if you have time I would wait for another person to answer as well because I'm terrible at statistics :(

6 0
3 years ago
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