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alukav5142 [94]
3 years ago
6

The area of a square is 64n^36 square units. What is the side length of one side of the square? HURRY!!!!

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0

Answer:

Step-by-step explanation:

√(64n^36) = 8n^18 the side length

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A model for the surface area of a human body is given by S = 0.1091w0.425h0.725, where w is the weight (in pounds), h is the hei
saveliy_v [14]

Answer:

2.3%

Step-by-step explanation:

Surface area of a human body is given by -

S = 0.1901* w^{0.425}* h^{0.725}\\

Taking integral on both sides, we get -

In S = 0.425 ln w + 0.725 ln h + ln 0.1091\\\frac{dS}{S} = 0.425\frac{dw}{w} + 0.725\frac{dh}{h}\\

Since, the at most error in the surface area of a human body is 2%

Substituting this in above equation, we get -

\frac{dS}{S} \leq [0.425*0.02 + 0.725*0.02]\\\frac{dS}{S} \leq0.023\\

Thus, the maximum error is surface area is equal to

0.023 * 100\\= 2.3%

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3 years ago
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Answer:

A.  :)

Step-by-step explanation:

5 0
3 years ago
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Anna35 [415]
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8 0
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You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

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A pack with 6 cans of juice costs 3.48. What it the unit price?
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3.48/6 = 0.58 per can
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