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gtnhenbr [62]
3 years ago
8

A shipment of beach balls with a mean diameter of 28 cm and a standard deviation of 1.3 cm is normally distributed. By how many

standard deviations does a beach ball with a diameter of 26.7 cm differ from the mean?
A-1
B-1.3
C-2
D-3
Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
6 0

Answer:

A. -1

Step-by-step explanation:

We have been given that a shipment of beach balls with a mean diameter of 28 cm and a standard deviation of 1.3 cm is normally distributed.  

Since z-score represents that a raw score is how many standard deviation above or below mean.

To solve our given problem we will use z-score formula.

z=\frac{x-\mu}{\sigma}, where,

z=\text{z-score},

x=\text{Raw score},

\mu=\text{Mean},

\sigma=\text{Standard deviation}.

Upon substituting our given values in z-score formula we will get,

z=\frac{26.7-28}{1.3}

z=\frac{-1.3}{1.3}

z=-1

Therefore, a beach ball with a diameter of 26.7 cm differs -1 standard deviation from the mean and option A is the correct choice.

ipn [44]3 years ago
5 0

Answer: 1

Step-by-step explanation: trust me, I took the test

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