Draw a bar and draw little squares inside the box not the bar and then shade the boxes this will represent the number
We can write a proportion for this problem
10,000drops of a liquid is 10 fluid ounces
100 drops of a liquid is x fluid ounces
x=100*10/10000 =1/10 = 0.1 fluid ounces
2.25 for 6 would be 0.375 per one of them
1.30 for 4 would be 0.325 per one of them
0.97 for 2 would be 0.485 per one of them
Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
Probability of heads or tails is .5
so you do (.5)^3 and you get D = 0.125