Answer:
m=3
Step-by-step explanation:
Answer:
x² + 2x + (3 / (x − 1))
Step-by-step explanation:
Start by setting up the division:
.........____________
x − 1 | x³ + x² − 2x + 3
Start with the first term, x³. Divided by x, that's x². So:
.........____x²______
x − 1 | x³ + x² − 2x + 3
Multiply x − 1 by x², subtract the result, and drop down the next term:
.........____x²______
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
Repeat the process over again. First term is 2x². Divided by x is 2x. So:
.........____x² + 2x __
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
Multiply, subtract the result, and drop down the next term:
.........____x² + 2x __
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
.................-(2x² − 2x)
.................---------------
.....................................3
x doesn't divide into 3, so that's the remainder.
Therefore, the answer is:
x² + 2x + (3 / (x − 1))
Answer:
Integers are not closed under the DIVISION operation
Example:
(9 ÷ 2 = 4½)
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer: 9.2•10^7 kilometers
Step-by-step explanation:
5.8•10^7=58,000,000
1.5•10^8=150,000,000
150,000,000-58,000,000=92,000,000
92,000,000=9.2•10^7
