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4 years ago

OPEN ENDED QUESTION

Mathematics

1 answer:

UkoKoshka [18]4 years ago

6 0

209.95 to find the area/volume of a triangle you do base times hight divided by 2

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milo is five inches shorter than his brother, jayce. If milo is 42 inches tall, then how tall is jayce?i need to write this into

hram777 [196]

Answer:

Jace is 47 inches tall

Step-by-step explanation:

8 0

3 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

4 years ago

Read 2 more answers

A) Two angles are adjacent if their measures add up to 90°.

slavikrds [6]

Answer:

A) False

B) False

Step-by-step explanation:

A. Two angles whose measures add up to 90° are said to be complementary, while two angles are adjacent when formed beside each other. So, adjacent angles might be complementary or supplementary. Thus, the answer to the first part of the question is false.

B. When two angles share a side, they are said to be adjacent to each other. But supplementary angles add up to $180^{o}$ . Since adjacent angles might be complementary or supplementary, then the answer to the second part of the question is false.

4 0

3 years ago

The diagram shows a logo made from three circles

Nana76 [90]

Answer:

3cm+2cm+5cm=10cm

%=100

10*10=100

2cm*10=20%

Step-by-step explanation:

the shaded area is width of 2 2/10 or 20/100

8 0

3 years ago

Read 2 more answers

If a rectangle’s length and width are doubled, by what percentage does its area increase?

spayn [35]

Answer:

300%

Step-by-step explanation:

S = ab

S1 = 2a × 2b

S1 = 4ab

S1 = 400%ab

=>The area is increased by 300%

6 0

3 years ago