3 years ago

A large adult kangaroo can have a mass of 90,000 grams. How many kilograms is it. (1g =1,000g)

Mathematics

2 answers:

allochka39001 [22]3 years ago

5 0

$90,000/1,000=90$
Your answer is 90 kilograms.

liubo4ka [24]3 years ago

3 0

$1kg=1,000g!!!\\\\therefore\ 1g=\frac{1}{1,000}kg=0.001kg\\--------------------\\90,000g=90,000\cdot0.001kg=\boxed{90kg}\\\\Answer:\boxed{\boxed{90,000g=90kg}}$

You might be interested in

-y=x-2 What’s the answer

Georgia [21]

Answer: -y = - 2 x

Step-by-step explanation:

5 0

3 years ago

Write a numerator that makes the statement true. 1/2 < /10 < 4/5

juin [17]

Answer:

10/5

Step-by-step explanation:

Because 10 is half of 5 and they are asking what will make this statement true 1/2 is half too

3 0

3 years ago

Read 2 more answers

Help me with this please

Iteru [2.4K]

Answer: is it -3,11

Step-by-step explanation:

7 0

3 years ago

The equations 2 x minus 5 y = negative 5, 11 x minus 5 y = 15, 9 x + 5 y = 5, and 14 x + 5 y = negative 5 are shown on the graph

Dafna11 [192]

Answer:

See attached graph

Step-by-step explanation:

8 0

3 years ago

13. For the arithmetic sequence: 6, 12, 18, 24,...

serg [7]

a_15 = 90

a_n = 6n

Step-by-step explanation:

Given sequence is:

6, 12, 18, 24,...

First of all we have to find the common difference. The common difference is the difference between consecutive terms of an arithmetic sequence.

Here,

$d=a_2-a_1 = 12-6 = 6\\d=a_3-a_2= 18-12 = 6$

The general form for arithmetic sequence is:

$a_n=a_1+(n-1)d$

Putting the values for a_1 and d

$a_n=6+(n-1)(6)\\a_n=6+6n-6\\a_n=6n$

a) Find a15

$a_{15} = 6(15)\\=90$

b) Write an equation for the nth term.

The equation is: a_n=6n

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

#LearnwithBrainly

4 0

3 years ago