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Varvara68 [4.7K]
3 years ago
11

The radius of circle O is 28, and OC =9. What is the length of AB?

Mathematics
1 answer:
aksik [14]3 years ago
7 0
The answer:
the complement of the question proposed one of the choices given beneath:
a) 58.8
b) 53.0
c) 29.4
d) 26.5

as we observe at the figure, AOB an isosceles triangle, and OCB is a right triangle

consider OCB
OC =9, OB= radius = 28
the problem is how to find the length of CA, for that C is a midpoint of segment AB, so AC=BC

BC can be found by using pythagorean theorem
OB²= OC² + CB²,  this implies CB² = OB² - OC²

CB² = 28² - 9² = 784 - 81=703, therefore CB= sqrt (703)=26.51

CB=26.51, since CB= AC, so  AC=CB= 26.51

finally the <span>the length of AB is AB = 2 x CB = 2x AC= 2x 26.51= 53.0
</span>
the answer is b) 53.0

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The trigonometric ratios have been determined and the angles T and U are complementary.

<h3>What are Trigonometric Ratios?</h3>

Trigonometric Ratios are ratios of the side of a right-angled triangle. These are used to find the missing sides and angles of a right-angled triangle.

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The trigonometric ratios are as follows:

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7 0
1 year ago
Please help ASAP!!!!!
Over [174]

Answer:

 x = 17/2 = 8.500

Step-by-step explanation:

Equation at the end of step  1  :

 2 • (x - 5) -  7  = 0  

Step  2  :

Equation at the end of step  2  :

 2x - 17  = 0  

Step  3  :

Solving a Single Variable Equation :

3.1      Solve  :    2x-17 = 0  

Add  17  to both sides of the equation :  

                     2x = 17

Divide both sides of the equation by 2:

                    x = 17/2 = 8.500

4 0
3 years ago
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