Question

Suppose that instead of using natuarl logarithma to compute b, we use logarithms with the base 10 and define b=(log r)/(log 2). Does this change the value of b?

Answer 1

Answer:

Yes it changes the value of b.

Step-by-step explanation:

Natural log is log with base e = 2.71828.

$ln(2)=log_{e}(2)=0.693\\\\where as\\\\log_{10}(2)=0.301$

From this we can conclude that value b when calculated with log to base 10 instead of natural log, value of b will change.