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Pavel [41]
3 years ago
5

BRAINLIEST OFFERED! Solve and Show work!! : 2x²-1=x²+4x+11

Mathematics
1 answer:
Musya8 [376]3 years ago
3 0
First we want to put this into standard form.
Subtract (x^2+4x+11) from both sides
x^2-4x-12

Then factor the trinomial
(x-6)(x+2)

Use the zero product property to find roots
(x-6)=0
x=6

(x+2)=0
x=-2

Final answers: x=-2, x=6
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I’m not sure how to solve “system of equations”
natka813 [3]

Hey there! :)

Answer:

(2, -2)

Step-by-step explanation:

-2x + y = -6

4x + 3y = 2

We can begin by setting the first equation equal to y:

-2x + y = -6

Add 2x to both sides:

y = 2x - 6

Plug this equation for y into the second equation:

4x + 3(2x - 6) = 2

Distribute:

4x + 6x - 18 = 2

Combine like terms:

10x = 20

x = 2

Plug the value of 'x' into an equation to solve for 'y':

-2(2) + y = -6

-4 + y = -6

y = -2

Therefore, the solution is (2, -2)

7 0
3 years ago
What is the area of a triangle with vertices (3,0) (9,0) (7,6)
Nezavi [6.7K]

Answer:

The area of the triangle is of 21 units of area.

Step-by-step explanation:

The area of a triangle with three vertices (x_1,y_1),(x_2,y_2),(x_3,y_3) is given by the determinant of the following matrix:

A = \pm 0.5 \left|\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\1_3&y_3&1\end{array}\right|

In this question:

Vertices (3,0) (9,0) (7,6). So

A = \pm 0.5 \left|\begin{array}{ccc}3&0&1\\9&0&1\\7&7&1\end{array}\right|

A = \pm 0.5(3*0*1+0*1*7+1*9*7-0*7*1-0*9*1-3*1*7)

A = \pm 0.5*(63-21)

A = \pm 0.5*42 = 21

The area of the triangle is of 21 units of area.

5 0
3 years ago
An inequality for m is no greater than 35
kirza4 [7]

Answer:

<em>m</em> ≤ 35

Step-by-step explanation:

The variable "m" is no greater than 35.

Note that "no greater" means that it can be up to the certain number (in this case, 35), but cannot exceed it. Your answer will be:

<em>m</em> is less than or equal to 35, or <em>m</em> ≤ 35.

~

5 0
3 years ago
Please hurry. Solve the equation
Lelu [443]

The value of x is 5\sqrt[3]{25}.

Solution:

Given expression is -7=8-3 \sqrt[5]{x^{3}}.

Switch both sides.

8-3 \sqrt[5]{x^{3}}=-7

Subtract 8 from both side of the equation.

8-3 \sqrt[5]{x^{3}}-8=-7-8

-3 \sqrt[5]{x^{3}}=-15

Divide by –3 on both side of the equation.

$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}

\sqrt[5]{x^{3}}=-5

To cancel the cube root, raise the power 5 on both sides.

(\sqrt[5]{x^{3}})^5=(-5)^5

x^3=3125

To find the value of x, take square root on both sides.

\sqrt[3]{x^3}=\sqrt[3]{25}

x=5\sqrt[3]{25}

Hence the value of x is 5\sqrt[3]{25}.

5 0
3 years ago
Rewrite the expression in the form y^ny n y, start superscript, n, end superscript. \left(y^{^{\scriptsize -\dfrac12}}\right)^{4
sladkih [1.3K]

Answer

Today’s mathematicians would probably agree that the Riemann Hypothesis is the most significant open problem in all of math. It’s one of the seven Millennium Prize Problems, with a million dollar reward for its solution. It has implications deep into various branches of math, but it’s also simple enough that we can explain the basic idea right here.

There is a function, called the Riemann zeta function, written in the image above.

For each s, this function gives an infinite sum, which takes some basic calculus to approach for even the simplest values of s. For example, if s=2, then (s) is the well-known series 1 + 1/4 + 1/9 + 1/16 + …, which strangely adds up to exactly ²/6. When s is a complex number—one that looks like a+b, using the imaginary number —finding (s) gets tricky.

So tricky, in fact, that it’s become the ultimate math question. Specifically, the Riemann Hypothesis is about when (s)=0; the official statement is, “Every nontrivial zero of the Riemann zeta function has real part 1/2.” On the plane of complex numbers, this means the function has a certain behavior along a special vertical line. You can see this in the visualization of the function above—it’s along the boundary of the rainbow and the red. The hypothesis is that the behavior continues along that line infinitely.

The Hypothesis and the zeta function come from German mathematician Bernhard Riemann, who described them in 1859. Riemann developed them while studying prime numbers and their distribution. Our understanding of prime numbers has flourished in the 160 years since, and Riemann would never have imagined the power of supercomputers. But lacking a solution to the Riemann Hypothesis is a major setback.

If the Riemann Hypothesis were solved tomorrow, it would unlock an avalanche of further progress. It would be huge news throughout the subjects of Number Theory and Analysis. Until then, the Riemann Hypothesis remains one of the largest dams to the river of math research.

5 0
2 years ago
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