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barxatty [35]
2 years ago
9

Please i need help no links or files give me honest answer thanks!

Mathematics
2 answers:
klio [65]2 years ago
4 0
The correct answer is D on ingenuity
Digiron [165]2 years ago
3 0

Answer:

D)

Step-by-step explanation:

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At the candy store, Jonathan bought 1.74 pounds of gumdrops, 2.2 pounds of jellybeans, and 1.38 pounds of licorice. How much did
GenaCL600 [577]

Answer:

5.32 lbs

Step-by-step explanation:

add all of them together, this is common sense math you should know how to do this.

3 0
3 years ago
Read 2 more answers
If CD=18, find the value of EB.
aliina [53]

Step-by-step explanation:

Chord AB and Chord CD are equidistant from the center of the circle.

\therefore \: chord \: AB \cong chord \:  CD \\  \\  \therefore \:  \frac{1}{2} \:  \: AB \cong \frac{1}{2} \: \:  CD  \\  \\ \therefore \: EB = \frac{1}{2} \:  \times 18\\  \\  \huge \purple{ \boxed{\therefore \: EB =9}}

5 0
3 years ago
My last problem and I'm stuck please help!!​
WITCHER [35]
Answer is C= -125,125
4 0
3 years ago
HELP PLEASEEEEEEEEEEEEEEEE
Nady [450]

Answer:

1\frac{3}{4}

Step-by-step explanation:

To find the answer, we divide the number of apples by the number of bags. This means we do 7 ÷ 4

7 ÷ 4 = 1.75

1.75 in fraction form is 1\frac{3}{4}

3 0
3 years ago
Read 2 more answers
The mean percentange of a population of people eating out at least once a week is 57℅
Sidana [21]

Answer:

<u>The correct answer is B. between 56.45% and 57.55% </u>

Complete statement and question:

The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume that a sample size of 40 people was surveyed from the population a significant number of times. In which interval will 68% of the sample means occur?

between 55.89% and 58.11%

between 56.45% and 57.55%

between 56.54% and 57.46%

between 56.07% and 57.93%

Source: brainly.com/question/1068489

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean percentage of a population of people eating out at least once a week  = 57%

Standard deviation = 3.5%

Sample size = 40

Confidence level = 68%

2. In which interval will 68% of the sample means occur?

For answering this question, we should find out the standard deviation of the sample, using this formula:

Standard deviation of the sample = Standard deviation of the population/√Sample size

Standard deviation of the sample = 3.5/√40

Standard deviation of the sample = 3.5/6.32

Standard deviation of the sample = 0.55

Let's recall that a confidence level of 68% means that 68% of the sample data would have a value between the mean - 1 time the standard deviation of the sample and the mean  + 1 time the standard deviation of the sample. Thus:

57 - 1 * 0.55 = 57 - 0.55 = 56.45

57 + 1  * 0.55 = 57 + 0.55 = 57.55

<u>The correct answer is B. between 56.45% and 57.55% </u>

7 0
3 years ago
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