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dem82 [27]
3 years ago
7

Solve one of the equations below. You must show your work. Tell whether it has one solution, an infinite number of solutions, or

no solutions.
(a) 6x + 4x - 6 = 24 + 9x

(b) 25 - 4x = 15 - 3x + 10 - x

(c) 4x + 8 = 2x + 7 + 2x - 20
Mathematics
1 answer:
Andrew [12]3 years ago
3 0

A. 6x + 4x - 6 = 24 + 9x

 10x -6 = 24 + 9x

       +6   +6

10x = 30 + 9x

-9x            -9x

1x = 30 this has an infinite number of solutions.

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1. Which score is the mode? 92.

2. Which score is the median? 92.

3. On which test did students average a 91? 3.

Step-by-step explanation:

Completed this on Edge!

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3 years ago
Which point is NOT correctly placed on this number line?
Tom [10]

Answer:

Point R at 7/2

If it is wrong then the other answer is probably Point Q.

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Find the area of the following shape. (8 points)<br><br> what is the answer?
Ivenika [448]

Answer:

72 square units

Step-by-step explanation:

  1. Identify the height
  2. Identify the length
  3. Multiply those two together
  4. That is your answer

H = 9 units

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A = 72 square units

8 0
2 years ago
How can we solve this?
Delvig [45]
Both angles will equal 180, as there is a line bisecting line AB to create the two angles.

Set up the following equation to have both angles equal 180:

(x + 35) + (x - 23) = 180

x + 35 + x - 23 = 180

Combine like terms:

x + x = 2x
35 - 23 = 12

2x + 12 = 180

Subtract 12 from both sides:

2x = 168

Divide both sides by 2:

x = 84

We now know the value of x, so plug it into the equation we set up:

(84 + 35) + (84 - 23) = 180

119 + 61 = 180

An obtuse angle will have a measure above 90 degrees. The number on the left side that is above 90 degrees is 119. This would be the measure for the obtuse angle.

The obtuse angle is 119 degrees wide.
8 0
3 years ago
If angle 0 is in quadrant I, what is the value of
Brilliant_brown [7]

Answer:

the \: answer \: is \: c \:  =  -  \frac{ \sqrt{14} }{5}

Step-by-step explanation:

\sin^{2}0 + ( \frac{ \sqrt{11} }{5} ) ^{2}  = 1( \sin^{2}0 +  \cos^{2} 0 = 1)

{ \sin }^{2}0 +  \frac{11}{25} = 1   \\  { \sin }^{2}0 =  \frac{14}{25}

\sin0_{1} =  -  \frac{ \sqrt{14}}{5} while \sin0_{2} =  \frac{ \sqrt{14} }{5}

  • Therfore theta is QI
  • Therfore sin theta >0
  • therefore \:  \sin0 =  \frac{ \sqrt{14} }{5}
4 0
2 years ago
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