Answer:
m<F = 53
Step-by-step explanation:
Exterior angles thm:
5x - 10 + 3x + 14 = 100
8x + 4 = 100
8x = 104
x = 13
m<F:
3x + 14
3(13) + 14
39 + 14
53
Answer:
no they'll be larger on a dilation image than a preimage
Step-by-step explanation:
hope this helped :)
Answer:
Step-by-step explanation:
ok its AAS because if you see the most aperent thing on the trangle is that
Answer:
![\large \boxed{\text{Q31, D. 6.00 F; 32. C. N21.75; Q33. A. 168.00 F}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7BQ31%2C%20D.%206.00%20F%3B%2032.%20C.%20N21.75%3B%20Q33.%20A.%20168.00%20F%7D%7D)
Step-by-step explanation:
Your graph is hard to read, so I re-drew it as best I could.
You must first develop an equation relating francs and naira.
The line goes through the origin, so the general equation is
y = kx
One of the points is (40,240).
![\begin{array}{rcl}F & = &k \times N\\240 & = &k \times 40\\k & = & \dfrac{240}{40}\\\\k&=&\textbf{6 F/N}\\\end{array}\\\text{The equation is $\large \boxed{\mathtbf{F = 6 N}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7DF%20%26%20%3D%20%26k%20%5Ctimes%20N%5C%5C240%20%26%20%3D%20%26k%20%5Ctimes%2040%5C%5Ck%20%26%20%3D%20%26%20%5Cdfrac%7B240%7D%7B40%7D%5C%5C%5C%5Ck%26%3D%26%5Ctextbf%7B6%20F%2FN%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20equation%20is%20%24%5Clarge%20%5Cboxed%7B%5Cmathtbf%7BF%20%3D%206%20N%7D%7D%24%7D)
Q 31.
![\begin{array}{rcl}F & = &6N\\& = & 6 \times 1.00\\& = & \mathbf{6.00}\end{array}\\\text{The equivalent value of N1.00 is $\large \boxed{\textbf{6.00 F}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7DF%20%26%20%3D%20%266N%5C%5C%26%20%3D%20%26%206%20%5Ctimes%201.00%5C%5C%26%20%3D%20%26%20%5Cmathbf%7B6.00%7D%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20equivalent%20value%20of%20N1.00%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B6.00%20F%7D%7D%24%7D)
Q 32.
![\begin{array}{rcl}F & = &6N\\130.5& = & 6 N\\N&=& \dfrac{130.5}{6}\\\\& = & \mathbf{21.75}\\\end{array}\\\text{The equivalent value of 130.5 F is $\large \boxed{\textbf{N21.75}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7DF%20%26%20%3D%20%266N%5C%5C130.5%26%20%3D%20%26%206%20N%5C%5CN%26%3D%26%20%5Cdfrac%7B130.5%7D%7B6%7D%5C%5C%5C%5C%26%20%3D%20%26%20%5Cmathbf%7B21.75%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20equivalent%20value%20of%20130.5%20F%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7BN21.75%7D%7D%24%7D)
Q 33.
![\begin{array}{rcl}F & = &6N\\& = & 6 \times 28.00\\& = & \mathbf{168.00}\end{array}\\\text{An amount of N28.00 is $\large \boxed{\textbf{168.00 F}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7DF%20%26%20%3D%20%266N%5C%5C%26%20%3D%20%26%206%20%5Ctimes%2028.00%5C%5C%26%20%3D%20%26%20%5Cmathbf%7B168.00%7D%5Cend%7Barray%7D%5C%5C%5Ctext%7BAn%20amount%20of%20N28.00%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B168.00%20F%7D%7D%24%7D)
Answer:
Step-by-step explanation:
The total number of claim is the sum S of 1250 independent random variables,
each having poisson distribution with mean μ = 2
Since the Variance of poisson distribution is equal to its mean ,
the standard deviation of this is
![\sigma= \sqrt{2}](https://tex.z-dn.net/?f=%5Csigma%3D%20%5Csqrt%7B2%7D)
By the CLT is follow that S is approximately normal with mean 1250*2 =2500
and standard deviation ![\sqrt{1250} *\sqrt{2} =50](https://tex.z-dn.net/?f=%5Csqrt%7B1250%7D%20%2A%5Csqrt%7B2%7D%20%3D50)
Hence, the probability to compute is
![P(2350\leq S\leq 2600)=P(\frac{2450-2500}{50} \leq \frac{S-2500}{50} \leq \frac{2600-2500}{50} )\\\\=P(-1](https://tex.z-dn.net/?f=P%282350%5Cleq%20S%5Cleq%202600%29%3DP%28%5Cfrac%7B2450-2500%7D%7B50%7D%20%5Cleq%20%5Cfrac%7BS-2500%7D%7B50%7D%20%5Cleq%20%5Cfrac%7B2600-2500%7D%7B50%7D%20%29%5C%5C%5C%5C%3DP%28-1%3C2%3C2%29%5C%5C%5C%5C%3DP%282%5Cleq%202%29-P%282%5Cleq%201%29%5C%5C%5C%5C%3D0.977249868-0.15365525%5C%5C%5C%5C%3D0.818594614%5C%5C%5C%5C%3D0.82)