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3 years ago

What is the rate of change for y = -3x + 2 over the interval [-3, 4]?

1 answer:

4 0

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
\stackrel{y}{f(x)}= -3x+2 \qquad 
\begin{cases}
x_1=-3\\
x_2=4
\end{cases}\implies \cfrac{f(4)-f(-3)}{4-(-3)}
\\\\\\
\cfrac{[-3(4)+2]~~-~~[-3(-3)+2]}{4+3}\implies \cfrac{-10~~-~~[11]}{7}
\\\\\\
\cfrac{-21}{7}\implies \cfrac{-3}{1}\implies -3$

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Terrence opens a savings account with a deposit of $1000. After 1 year he receives $50 in interest. What is the annual interest

geniusboy [140]

Answer:

Step-by-step explanation:

So, I'm pretty sure this is a problem about compound interest.

The formula for compound interest is A = p(1 + r/n)^nt

For this problem, $1000 is p, the initial amount; A is the total amount, or $1050.

What the problem is asking for is r, the interest rate, which is divided by n. N is the number of times the interest rate is compounded per year; Since the question is asking for the annual interest rate, N would be equal to 1. And because Terrence is has only left his money in for a year, t would also be equal to one.

So, by filling in the formula some, we get this:

$1050 = $1000(1 + r/1)^1*1

To find r, we would need to isolate it in the problem.

1. First, distribute $1000 to the parenthesis(keep in mind that 1000, is also equal to 1000/1:

1050 = (1000 + 1000r/1)^1

2. Then subtract 1000 from both sides:

50 = (1000r/1)^1

3. Multiple both sides by one:

50 = (1000r)^1

4. Divide both sides by 1000:

.05 = r^1 or .05 = r.

The answer is A, 5%.

8 0

4 years ago

PLEASE HELP ASAP. Madge leaves her home at 8:05 to go to school. The drive takes one-third hour each way. If she is at school fo

Zielflug [23.3K]

3:45

1/3 of an hour is 20 minutes.
8:05 + 20min = 8:25
8:25 + 7 hrs = 3:25
3:25 + 20 min= 3:45

5 0

3 years ago

Read 2 more answers

The pizza shop offers a 15 percent discount for veterans and senior citizens. If the price of a pizza is $12, how would you find

Rasek [7]

Answer:

All you would do is times 12 by .15 or 15% you get 1.8 then all you do is 12 minus 1.8 you get $10.20 that is the price of a discounted pizza

I hope this helps

4 0

3 years ago

Read 2 more answers

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

I need help please...

azamat

E' = (-9, -2)

F' = (-8, -2)

G' = (-8, -4)

6 0

3 years ago

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