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kirill [66]
2 years ago
14

Can you answer these 3 questions for me plz

Mathematics
2 answers:
finlep [7]2 years ago
4 0
A.
1hr \: 15min = 75min

c = 0.22t = 0.22 \times 75 = 16.5

cost is $16.50

B.

26.40 = 0.22 \times t

rearrange to solve for t:

t = \frac{26.40}{0.22} = 120min

C. This is the same as part B, only the rate changed

t = \frac{26.40}{0.25} = 105.6min

they ask for the greatest number of minutes, so we round down (take the floor of the value).

the answer is 105 minutes.
victus00 [196]2 years ago
4 0
The cost is a function of time in minutes, and t represents minutes.

Part A.

1 hour + 15 minutes = 60 minutes + 15 minutes = 75 minutes

c = 0.22t

For 75 minutes, t = 75

c = 0.22 * 75

c = 16.5

Answer for Part A.: The cost of a 1 hour 15 minute call is $16.50

Part B.

Now we are given the cost, c, and we need to find t, the time in minutes.

c = 0.22t

26.4 = 0.22t

Divide both sides by 0.22

120 = t

t = 120

Answer to Part B.: 120 minutes.

Part C.

The new cost is now 0.25t.
We want the cost to be at most $26.40.
That means the cost must be less than or equal to $26.40.

0.25t \le 26.4

t \le 105.6

The number of minutes must be less than or equal to 105.6 minutes.
Since the calls are charged by whole minutes, the longest call can be 105 minutes.

Answer to Part C.: 105 minutes
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Unit rate describes how many units of the first type of quantity corresponds to one unit of the second type of quantity. Some common unit rates are miles, per hour, cost per item, earnings and per week

Step-by-step explanation:

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ddd [48]
The unit disk can be parameterized by the function

\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)

where 0\le r\le 1 and 0\le\theta\le2\pi. The squared distance between any point in this region (x,y)=(r\cos\theta,r\sin\theta) and the point (1, 1) is

(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2
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=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2
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The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

\dfrac{\displaystyle\iint_{x^2+y^2
=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}
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Step-by-step explanation:

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The odds against Carl beating his friend in a round of golf are 9:7. Find the probability that Carl will lose?
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The ratio 9:7 gives you following statement:

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Then the probability that Carl will lose is

Pr(\text{Carl will lose})=\dfrac{7}{16}.

Answer: Pr(\text{Carl will lose})=\dfrac{7}{16}.


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