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MissTica
3 years ago
12

g Define two jointly distributed continuous random variables, X and Y, as the fluid velocities measured in meters/second at two

different locations, A and B, respectively, in a pipe flow system. The marginal density function for X is . Additionally, the conditional density function is . i. Are X and Y independent? Justify your answer. ii. If the fluid velocity at location A is 0.5 m/s, determine the probability that location B has a fluid velocity that is less than the fluid velocity of location A. iii. Find the probability density function f(x,y). iv. Find the marginal density function h(y). v. Find the conditional density

Mathematics
1 answer:
sergey [27]3 years ago
7 0

Answer:

Attached is the complete question and solutions

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Calculate the missing terms of the geometric sequence ...,3072, 7,2,7, 12,.... Select all that apply.
miskamm [114]

Answer:

The missing terms are 768, 192, 48.

Step-by-step explanation:

From the given geometric sequence

First term= a_1=3072

Fifth Term= a_5=12  

The general form of a geometric sequence is:

a_n=ar^(n-1)

here a_nis the nth term, a is the first term and r is the common ratio.

We will use the general form for term 5 to calculate the value of r.

So the general form for term 5 will be

a_5=3072* r^(5-1)

Putting the value of a_5

12=3072* r^4

r^4=  12/3072

r^4=  1/256

r^4=  1/[(4)^4]

Solving for r  

r=  1/4

Now  

a_2= ar^(2-1)

a_2=3072*r

a_2=3072*  1/4

a_2=768

a_3= ar^(3-1)

a_3=3072*r^2

a_3=3072*(1/4)^2

a_3=3072*  1/16

a_3=192

a_4= ar^(4-1)

a_4=3072*r^3

a_4=3072*(1/4)^3

a_4=3072*  1/64

a_4=48

6 0
3 years ago
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