Substitute the given values in the Law of Sines and find that the measure is 24.72°
![\frac{15 + 18 + 16 + x}{4} = 17 \\ \frac{49 + x}{4} = 17 \\ 49 + x = 17 \times4 \\ 49 + x = 68 \\ x = 68 - 49 \\ x = 19](https://tex.z-dn.net/?f=%20%5Cfrac%7B15%20%2B%2018%20%2B%2016%20%2B%20x%7D%7B4%7D%20%20%3D%2017%20%20%5C%5C%20%20%5Cfrac%7B49%20%2B%20x%7D%7B4%7D%20%20%3D%2017%20%5C%5C%2049%20%2B%20x%20%3D%2017%20%5Ctimes4%20%5C%5C%2049%20%2B%20x%20%3D%2068%20%5C%5C%20x%20%3D%2068%20-%2049%20%5C%5C%20x%20%3D%2019)
hope this helps! ask if you have anymore questions
What you must do for this problem is to re-imagine the equation in "vertex form"
Vertex form:
![y=a(x-h)^{2} +k](https://tex.z-dn.net/?f=y%3Da%28x-h%29%5E%7B2%7D%20%20%2Bk)
where "h" shifts the graph to the right if "h" is positive" and to the left if "h" is negative. K shifts the graph up and down.
![g(x)=a(x-h)^{2} +k](https://tex.z-dn.net/?f=g%28x%29%3Da%28x-h%29%5E%7B2%7D%20%2Bk)
![g(x)=1(x-1)^{4} +0](https://tex.z-dn.net/?f=g%28x%29%3D1%28x-1%29%5E%7B4%7D%20%2B0)
a=1
h=1
k=0
So, your final answer should be:
Let's find the formula for a rectangle:
2L+2W= 90
Now we know the length is equal to 6 more than 2 times the width, let's make the equation.
L=2w+6
Let's plug that in for L in the first equation.
2(2w+6)+2w=90
4w+12+2w
6w+12=90
6w=78
78÷6=13=w
The width is 13, but we need the length. We know the length is equal to 6 more than 2 times the width.
13×2= 26+6= 32
So, the length of the rectangle is 32 ft.
Answer:
π·r^3 + 7·π·r^2 = r^2·π·(r + 7)
r + 7 is the height of the cylinder.