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Ivenika [448]
3 years ago
5

You are working on an experiment where you want to test the effects of caffeinated beverages on the behavior of cats. You will t

est this by giving cats an expensive brand name cola. You will need exactly 2L of cola for your experiment. When you are at the store you see that you can buy a 2 liter bottle of cola for 2.25. Alternatively you can buy 500ml cans of cola. Each can costs 50 cents. Which of the following should you purchase to be the most cost effective?
A. 4 cans B. 1 bottle C. 2 bottles D. 1 can F. 2 cans G. 3 cans E. 5 cans
Mathematics
1 answer:
vichka [17]3 years ago
6 0
For the experiment, you need 2L of cola. Your first option would be to purchase 1 2L bottle of cola for $2.25. 

To calculate the second option, let's convert milliliters to liters first. There are 1,000 milliliters in 1 liter. With this, we know that there are 2,000 milliliters in 2 liters. Option 2 comes in 500-milliliter cans, which means that you would need 4 of them (2,000/500 = 4). 4 cans multiplied by $0.50 would cost you $2.00. 

Let's check the cost of your answer options.
A. 4 cans - As seen above, this would cost $2.00.
B. 1 bottle - From the question, we know this would cost $2.25.
C. 2 bottles - This would be more soda than you need and would cost $4.50 ($2.25x2)
D. 1 can - This would be .5L and not enough soda for the experiment.
E. 5 cans - This would cost $2.50, but would be an extra 500mL of soda.
F. 2 cans - This would only be 1L of soda and not enough for the experiment.
G. 3 cans - This would be 1.5L of soda and not enough for the experiment either.

For the best price option, you would choose A (four cans of soda). This would give you the amount of soda that you need at the lowest price.
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Find the sum. r/r^2-q^2 + 5/r+q​
pickupchik [31]

Answer:

The answer is:  

\frac{6r-5q}{r^2-q^2}

which agrees with the last answer option (D) in the list.

Step-by-step explanation:

In order to add rational expressions, we need to express them with the same denominator. Therefore we examine what factors there are in the first denominator, which happens to be a difference of squares which is readily factored out as:

r^2-q^2=(r+q)\,(r-q)

the second denominator consists of only one of these factors: (r+q), then in order to express both rational expressions with the same common denominator, we multiply numerator and denominator of the second fraction by the factor: (r-q)

Then we get two expressions that can be easily added as shown below:

\frac{r}{(r+q)\,(r-q)} +\frac{5\,(r-q)}{(r+q)\,(r-q)} =\frac{r+5(r-q)}{(r+q)(r-q)} =\frac{r+5r-5q}{(r+q)\,(r-q)} =\frac{6r-5q}{r^2-q^2}

7 0
3 years ago
Use the digits 1,3,4,and 7 to create two whole numbers whose product is estimated to be about 600
blagie [28]
34 x 17  (round the 2 numbers)
30 x 20
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Also, 34 x 17 = 578, which rounds to 600


The answer is 34 and 17

7 0
3 years ago
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Please sombody actually help me im stuck on this.​
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Answer:

A=6

B=19

C=55

D=119

E=70

7 0
3 years ago
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Which of the following is the graph of y = 3x2 + 6?
natali 33 [55]

Answer:

what are the graphs?

Step-by-step explanation:

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How do I solve 5/6(3/8-x)=16
Diano4ka-milaya [45]

First, distribute the 5/6:

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Multiply everything by 48 to get rid of fraction:

15 - 40x = 768

-40x = 768

x= -19 1/5

7 0
3 years ago
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