Given:
A line through the points (7,1,-5) and (3,4,-2).
To find:
The parametric equations of the line.
Solution:
Direction vector for the points (7,1,-5) and (3,4,-2) is



Now, the perimetric equations for initial point
with direction vector
, are



The initial point is (7,1,-5) and direction vector is
. So the perimetric equations are


Similarly,


Therefore, the required perimetric equations are
and
.
Answer:
b/a
Step-by-step explanation:
Given,(b^-2)/a*(b^-3)
or,(b^-2+3)/a
or,b/a
(5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m)
P = 53/10 + 5 3/10 + 5 3/10 + 5 3/10
P = 53/10 + 53/10 + 5 3/10 + 5 3/10
P = 53/5 + 5 3/10 + 5 3/10
P = 53/5 + 53/10 + 5 3/10
P = 159/10 + 5 3/10
P = 159/10 + 53/10
P = 106/5
P = 21 1/5 meters
Answer: 21 1/5 meters (Decimal: 21.2m)
Hope that helps!!!! Have a great day!!!! : )
Should be D. Let me know if you need more of an explanation.
Answer:
5,7
Step-by-step explanation: