25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
(-infinity,2)U(2,infinity)
{x/xnot=2}
this is what I found
Pls help its due tomorrow
Hi!
<h3>Let's do the first step (add 2x). </h3>
5 + 3x + 2x = -2x + 2x + 9
<em>5 + 5x = 9</em>
<h3>Our goal is to isolate x on one side, so the next step would be to subtract 5 (or add -5).</h3>
5 + -5 + 5x = 9 + -5
<u><em>5x = 4</em></u>
<h2>The answer is B. add -5</h2><h3><em>And if you want to finish solving, you would divide by 5 on both sides.</em></h3>
5x/5 = 4/5
x = 0.8
Hope this helps! :)
-Peredhel
Answer:
(2 + 1)^2 + 2 = 10 - 6
Falso
Step-by-step explanation:
109 / 5000
El lado izquierdo
11
no es igual al lado derecho
4
, lo que significa que la declaración dada es falsa.
Falso
