Answer:
y = 0
Step-by-step explanation:
Plug in 28 for x. Solve for the equation:
x + 3y = 28
(28) + 3y = 28
Isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 28 from both sides:
28 (-28) + 3y = 28 (-28)
3y = 0
Isolate the variable, y. Divide 3 from both sides:
(3y)/3 = (0)/3
y = 0
y = 0 is your answer.
~
In this question, you are only able to cancel out the (x + 5). The others are unable to be cancelled.
Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
Answer:
4K
Step-by-step explanation:
= K ( multiply both sides by 24 to clear the fraction )
J = 24K ( divide both sides by 6 )
= 4K
4/81 (?)
not sure if that is 100% correct