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Goryan [66]
2 years ago
6

The isosceles triangle ABC has an area of 48 square units if AB=12 what is the perimeter of Abc in units?

Mathematics
1 answer:
erastovalidia [21]2 years ago
5 0

Answer:

the answer would be 4 because you multiply

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263.000 divided by 7
Readme [11.4K]

Answer:

the answer is 37.5714285714

Step-by-step explanation:

hope it helps have a nice day or night

:)

4 0
2 years ago
Which function is equivalent to the inverse of y=sec(x)
kipiarov [429]
From the identity:

sec(x)= \frac{1}{cos(x)}


f(x)=sec(x)= \frac{1}{cos(x)}

the inverse of f is g such that f(g(x))=x,

we must find g(x), such that \frac{1}{cos[g(x)]}=x

thus, cos[g(x)]= \frac{1}{x}

g(x)=cos^{-1} (\frac{1}{x})


Answer: b. g(x)=cos^-1(1/x)   
6 0
3 years ago
tickets for a football match are sold at $30 for adults and $15 for children a company bought 28 tickets if x of these tickets w
anzhelika [568]
First, we must let:
   x = number of tickets intended for adults
   y = number of tickets intended for children.

a. Write in terms of x the number of tickets for children
     Solution:
           x + y = 28   ⇔    y = 28 - x   (equation 1)
       To answer in terms of x:
           no. of tickets for tickets for children = 28 - x

b. the amount spent on tickets for adults
    Solution:  $30 is the cost of ticket per adult and there are x number of tickets intended for adults.
           Therefore, 
            amount spent on ticket for adults = 30x

c. the amount spent on the tickets.
     Solution:
       $ 15  = cost of ticket per child
       $ 30 = cost of ticket per adult

      total amount spent on tickets = 30x + 15y    ⇒   (equation2)
  substitute equation 1 to equation 2.
  (equation 1)   y = 28 - x
  (equation 2)   total amount spent on tickets = 30x + 15y
                        total amount spent on tickets = 30x + 15(28-x)
                        total amount spent on tickets = 30x + 420 - 15x
                        total amount spent on tickets = 15x + 420
4 0
3 years ago
The diameter and height of this cylinder are equal to the side length,S,of the cube in which the cylinder is imscribed. What is
max2010maxim [7]
V=B\times H
V=\pi r^{2}h
V=\pi (\frac{d}{2})^{2}h
V=\pi (\frac{s}{2})^{2}s
V=\pi (\frac{s^{2}}{4})s
V=\frac{\pi s^{3}}{4}
3 0
3 years ago
Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
2 years ago
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