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Sedbober [7]
3 years ago
10

A math classroom has 30 students. The teacher assigned the students a project and told them they could turn it in on Monday, Tue

sday, or Wednesday. 12 of the students turned the project in on Monday. 13 of the students turned the project in on Tuesday. The rest of the students turned the project in on Wednesday. How many students turned their project in on Wednesday?
Mathematics
2 answers:
beks73 [17]3 years ago
8 0

Answer:

5 students.

30 - 12 - 13 = 5.

miv72 [106K]3 years ago
4 0

Answer:

The answer is 5

Step-by-step explanation:

We need to find out how many students turned in the project on Wednesday. In order to do this, this is what we need to do.

1. First we need to subtract 12 from 30 since 12 is how many students turned in the project on Monday.

2. 30 - 12 = 18

So now we have 18.

3. Next we need to subtract 13 from 18 since we know that 13 is how many students turned in the project on Tuesday.

4. 18 - 13 = 5

At the end we end up with 5.

So 5 students turned in the project on Wednesday.

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natta225 [31]

Answer:

UV=29

Step-by-step explanation:

In right triangles AQB and AVB,

∠AQB = ∠AVB ...(i)  {Right angles}

∠QBA = ∠VBA ...(ii)  {Given that they are equal}

We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle


∠AQB+∠QBA+∠BAQ=180 ...(iii)

∠AVB+∠VBA+∠BAV=180 ...(iv)


using (iii) and (iv)

∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV

∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV  (using (i) and (ii))

∠BAQ=∠BAV...(v)


Now consider triangles AQB and AVB;

∠BAQ=∠BAV  {from (v)}

∠QBA = ∠VBA {from (ii)}

AB=AB  {common side}

So using ASA, triangles AQB and AVB are congruent.

We know that corresponding sides of congruent triangles are equal.

Hence

AQ=AV

5x+9=7x+1

9-1=7x-5x

8=2x

divide both sides by 2

4=x

Now plug value of x=4 into UV=7x+1

UV=7*4+1=28+1=29

<u>Hence UV=29 is final answer.</u>

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3 years ago
Where is the most optimal position to send your bean bag in relation to opponent's bean bag?​
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Step-by-step explanation:

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Solve this a interval notation. 5 greater than or equal to |4-2x|
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4 0
3 years ago
Could someone answer and explain these please? Thank you!
Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

x=(10 \times t)+(1 \times u)

x=10t+u

The two digit number 'y' is obtained by reversing the digits of x.

So, y=(10 \times u)+(1 \times t)

y=10u+t

Now, the value of x-y is expressed as:

x-y=(10t+u)-(10u+t)

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So, 9(t-u) is equivalent to (x-y).

Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = \frac{a}{1-r}

Since, the sum of the given infinite geometric series = 200

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Since, r=0.15 (given)

\frac{a}{1-0.15}=200

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a=0.85 \times 200

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The nth term of geometric series is given by ar^{n-1}.

So, second term of the series = ar^{2-1} = ar

Second term = 170 \times 0.15

= 25.5

So, the second term of the geometric series is 25.5






Step-by-step explanation:


8 0
3 years ago
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