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GrogVix [38]
3 years ago
5

What is the solution to the equation below? log20x3 - 2 logx=4

Mathematics
1 answer:
atroni [7]3 years ago
3 0

Answer:

The value of x  is 500

Step-by-step explanation:

Given as :

log20x³ - 2 logx = 4

<u>From log property </u>

alogb = logb^{a}  

So , log20x³ -  logx² = 4

<u>Again From log property </u>

log m- log n = log\frac{m}{n}

So,  log20x³ -  logx² =  log\frac{20x^{3}}{x^{2}}

Or,   log\frac{20x^{3}}{x^{2}} = 4

So \frac{20x^{3}}{x^{2}} = 10^{4}      ( antilog property)

Or, 20 x = 10000

∴         x = 500

Hence The value of x  is 500    Answer

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Answer:

Step-by-step explanation:

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At some point you are going to have to turn the equation around. This would not normally be your first step, but this time it is better to start with it.

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Notice that you have effectively changed the ≤ sign around, not because you have, but because the x reads differently now. It started out 9 - x ≤ 17 and when you finish solving it you get 8 is less than or equal to x. Entirely different.

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Hi,

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