Answer:
Since the balls are drawn with replacement, it means the individual probability remain constant,
I have solved this problem on paper (Figures Attached).
Thanks.
If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)
The total volume of the ball will be;
= Total volume - Volume of hollow part
= 4/3πr³ - 4/3πr³
= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³
= 4 × 3.14 × 9 - 4/3 × 3.14 × 8
= 113.04 - 33.52
= 79.52
If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;
= 79.52 × 3.25
= 258.44 g
Now, if there are 8 spheres in one box, the weight if box will be;
= 258.44 × 8
= 2,067.52 g
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Ahh! Finally done with this, if you have any doubt just do ask me :)
Answer:
371.2
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
Sum of first 4 numbers= 4*5= 20
This includes 3 + 4th number
Sum of last 4 numbers= 4*8= 32
This includes 4th number + 3
Sum of 7 numbers= 7*(6+4/7)= 46
This includes 3+4th number +3
Number common to both sets= (20+32)- 46 = 6
I believe the correct answer is 18
