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olasank [31]
3 years ago
6

Judy makes a lemon pie. Judy cuts the lemon pie into six equal pieces. Judy wants to share the pie with her friend, Edith. Judy

eats one piece of the lemon pie. Edith eats one piece of the lemon pie. Judy says that each of them are one - sixth of the lemon pie. Edith says that each of them are two sixths of the lemon pie. Who Is correct?
Mathematics
1 answer:
drek231 [11]3 years ago
8 0
Judith. In total they BOTH eat 2 sixths of the pie. But if you’re talking about EACH then then it’s one sixth
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-3+4p=-31 idk what it is
OLga [1]
4p = -28
divide each side by 4
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4 0
3 years ago
Read 2 more answers
"solve each system by graphing"
garik1379 [7]
Put them into y=mx+b
y=1/3x -1 
y=2/3x-4
Graph them. Where they touch is your answer. No touch? No solution. Same line? Infinite solutions.
Second set: Same thing.
Solution to first set is (9,2)
3 0
3 years ago
A mouse climbs up a well of 86 meters. It advances 14 meters during the night, but during the day it retreats 2. The mouse will
Deffense [45]

Step-by-step explanation:

we assume day and night are equally long.

and the mouse will start at night of day 1.

then, on day 2, it will first retreat 2 meters (during daylight) and then advance 14 meters (at night).

so, on every full day, the mouse will effectively advance 12 meters (-2 + 14 = 12).

with a starting value of 14 (the first night).

so, we are getting an arithmetic sequence

an = an-1 + c

c = 12 in our case.

a1 = 14

a2 = a1 + 12 = 14+12 = 26

a3 = a2 + 12 = a1 + 12 + 12 = 14 + 2×12 = 38

an = a1 + (n-1)×12 = 14 + 12(n-1)

at what n will it reach 86 ?

86 = 14 + 12(n-1) = 14 + 12n - 12 = 2 + 12n

84 = 12n

n = 7

so, on the 7th day the mouse will reach the surface (if we truly count the first starting night day 1 - this is up to your teacher, but I would).

7 0
2 years ago
The percentage of obese children aged 12-19 years in the United States is approximately P(t) = 0.04t + 4.6 if 0 ≤ t < 10 −0.0
Gwar [14]

Answer:

1975------ 4.8%

1990 ------ 11.48%

1985 ------ 8.51%

Step-by-step explanation:

Given

P(t) = 0.04t + 4.6 if 0 ≤ t < 10

P(t) = -0.01005t^2 + 0.945t - 3.4 if 10 ≤ t ≤ 30

Where

t:=0 implies year = 1970

Solving (a): Beginning of 1975.

First, we calculate the value of t

t = 1975 - 1970

t = 5

This falls in the range: 0 ≤ t < 10

So:

P(t) = 0.04t + 4.6

P(5) = 0.04 * 5 + 4.6

P(5) = 4.80

Solving (b): Beginning of 1990.

t = 1990 - 1970

t = 20

This falls in the range: 10 ≤ t ≤ 30

So:

P(t) = -0.01005t^2 + 0.945t - 3.4

P(20) = -0.01005*20^2 + 0.945*20 - 3.4

P(20) = 11.48

Solving (c): Beginning of 1985

t = 1985 - 1970

t = 15

This falls in the range: 10 ≤ t ≤ 30

So:

P(t) = -0.01005t^2 + 0.945t - 3.4

P(15) = -0.01005*15^2 + 0.945*15 - 3.4

P(15) = 8.51375

P(15) = 8.51

7 0
3 years ago
Use the quadratic formula to find the solutions to the quadratic equation
777dan777 [17]

Answer:

It will have complex and different roots.

Step-by-step explanation:

The solution is attached in the image below:

4 0
4 years ago
Read 2 more answers
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