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vodomira [7]
3 years ago
10

you roll a fair 6-sided die. What is P ( roll a 2 )? if necessary round your answer to 2 decimal places.

Mathematics
2 answers:
OLEGan [10]3 years ago
7 0

Answer:

There are 6 possible outcomes therefore the probability in fraction form is

\frac{1}{6}

to convert this to decimal form divide 1 by 6

1\div6=0.1666666666 or 0.17 after rounding

to turn this into a percentage move the decimal two places to the right

%16.66666666 or %16.67 after rounding

xxTIMURxx [149]3 years ago
6 0

Answer:

16.66%

Step-by-step explanation:

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(-10)^{-4}=\\
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Write 4/10 in lowest terms:
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Step-by-step explanation:

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Read 2 more answers
2. Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79. What did it cost 10 years ago? How long
Makovka662 [10]

Answer:

It cost $0.91 10 years ago.

It takes 10.24 years for the cost of bread to double.

Step-by-step explanation:

The equation for the price of bread after t years has the following format:

P(t) = P(0)(1+r)^{t}

In which P(0) is the current price, and r is the inflation rate, as a decimal.

If we want to find the price for example, 10 years ago, we find P(-10).

Inflation is at a rate of 7% per year. Evan's favorite bread now costs $1.79.

This means that r = 0.07, P(0) = 1.79. So

P(t) = P(0)(1+r)^{t}

P(t) = 1.79(1+0.07)^{t}

P(t) = 1.79(1.07)^{t}

What did it cost 10 years ago?

P(-10) = 1.79(1.07)^{-10} = 0.91

It cost $0.91 10 years ago.

How long before the cost of the bread doubles?

This is t for which P(t) = 2P(0) = 2*1.79. So

P(t) = 1.79(1.07)^{t}

2*1.79 = 1.79(1.07)^{t}

(1.07)^{t} = 2

\log{(1.07)^{t}} = \log{2}

t\log{1.07} = \log{2}

t = \frac{\log{2}}{\log{1.07}}

t = 10.24

It takes 10.24 years for the cost of bread to double.

5 0
3 years ago
Simplify the following expression:
aliya0001 [1]

Answer:

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Step-by-step explanation:

-1/3(6x+15)-3

-6/3x-15/3-3

-2x-5-3

-2x-8

7 0
3 years ago
If f(x)=|9-2x|,for which values of x will f(x)<3?
aleksley [76]
I think the answer is -4 if you subsitute x for 3
8 0
3 years ago
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