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kap26 [50]
3 years ago
8

rob is saving up to buy a new MP3 player for every $15 he earns babysitting he saves six dollars. on Saturday rob earned $75 bab

ysitting how much money did he save
Mathematics
2 answers:
Alex787 [66]3 years ago
3 0
The total amount of money is 75 dollars
There are 5 fifteens in 75 
There are 6 dollars saved everytime he makes 15 dollars
6 x 5 = 30
He saved 30 dollars 
Marat540 [252]3 years ago
3 0

Answer : He saved $30 money.

Step-by-step explanation :

when he earned $15 from babysitting, he saved money = 6 dollars

when he earned $1 from babysitting, he saved money = \frac{6}{15} dollars

when he earned $75 from babysitting, he saved money = \frac{6}{15}\times 75=30 dollars

Therefore, He saved $30 money.

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Giving brainliest & a thanks if you answer all of them
Kisachek [45]

Answer:

2) Mia needs to buy 3 packages of noisemakers

3)Mia needs to buy 4 packages of hats

4)Mia will dpend a total of $66

5 0
3 years ago
Suppose f is a continuous function on [-2, 2) such that
Leviafan [203]

Answer:

2. a and b only.

Step-by-step explanation:

We can check all of the given conditions to see which is true and which false.

a. f(c)=0 for some c in (-2,2).

According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.

b. the graph of f(-x)+x crosses the x-axis on (-2,2)

Let's test this condition, we will substitute x for the given values on the interval so we get:

f(-(-2))+(-2)

f(2)-2

-1-1=-3  lower limit

f(-2)+2

1+2=3 higher limit

according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.

c. f(c)<1 for all c in (-2,2)

even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.

The final answer is then 2. a and b only.

4 0
3 years ago
PLZ HELP! 20 POINTS!!
ivann1987 [24]
Given list of values
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}

Sort list A to get list B
B = {7, 9, 10, 13, 19, 20, 23, 23, 27, 28, 29, 34, 36, 36, 37, 40, 43}

The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43

Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)

Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
which is the list of all values lower or smaller than the median.
The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1

The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U

------------------------------------------------

Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43

This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1). 

5 0
3 years ago
Find the least number must be added to 4015 to make it a perfect square. also,find the square root of the perfect square so obta
Vladimir [108]

To solve this, I used guess and check.

I started by finding 60²=3600 and 70²=4900. 70² is too much, so I then did 65²=4,225.

After 65², I did 62²=3,844. I knew that was pretty close, so I did 64. 64²=4,096 and 63²=3,969. So, 64² was it.

4,096-4015=81

So, you would need to add 81 to 4015 in order to receive a perfect square, which is 64²(4,096).

7 0
3 years ago
Evaluate 2y²(x+y) when x = 1 and y = 5<br> Show working out
Harlamova29_29 [7]

Answer:

300

Step-by-step explanation:

2(5)²(1+5)

2(25)(6)

50(6)

300

4 0
3 years ago
Read 2 more answers
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