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Bezzdna [24]
2 years ago
9

In ΔABC, if m ∠A = m∠C, m∠B = ß (where ß is an acute angle), and BC = x, which expression gives the length of b, the side opposi

te ∠B ?

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
6 0

Answer:

The length of b is \sqrt{2x^2(1-cos\beta)}.

Step by step explanation:

Given information: In ΔABC, ∠A =∠C, ∠B = ß (where ß is an acute angle), and BC = x.

Since two angles are same therefore triangle ABC is an isosceles triangle and side AB and BC are congruent.

AB=BC=x

According to Law of cosine

b^2=a^2+c^2-2ac\cos B

b^2=x^2+x^2-2(x)(x)\cos \beta

b^2=2x^2-2x^2\cos \beta

b^2=2x^2(1-\cos \beta)

\sqrt{2x^2(1-cos\beta)}

Therefore the length of b is \sqrt{2x^2(1-cos\beta)}.

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