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Mazyrski [523]
3 years ago
14

I=E/R + r solve for r

Mathematics
1 answer:
zheka24 [161]3 years ago
4 0
For like lower case r?

then,

I = E/R + r

multiple by R to the other side and subtract E  

r= I * R - E

hope that helps
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Answer:

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then, the solution for this equation  is given by;


x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}              ......[1]

From the equation, 3x^2+14x+16=0 we have

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Substitute these values in [1] to solve for x;


x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-14\pm\sqrt{(14)^2-4(3)(16)}}{2(3)}              

or

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Simplify:

x=\frac{-14\pm\sqrt{4}}{6} =\frac{-14\pm 2}{6}

then,

x=\frac{-14+2}{6} =\frac{-12}{6} =-2 and

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Therefore, the solutions for the given equation is; x =-2 and x =-\frac{8}{3}



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Answer:

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