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3 years ago

Help me plzz I really need itttt

Mathematics

1 answer:

saveliy_v [14]3 years ago

4 0

Answer:

Step-by-step explanation:

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Which expression results from dividing 6x^8-4x^6 by 2x^2

pogonyaev

$\frac{6 {x}^{8} - 4 {x}^{6} }{2 {x}^{2} } = \frac{2 {x}^{6}(3 {x}^{2} - 2) }{2 {x}^{2} } = 2 {x}^{4}(3 {x}^{2} - 2)$

6 0

2 years ago

Read 2 more answers

the stove you have to bake in is an old one and only has the temperature in ° Fahrenheit. You are making rusks and have to dry t

nalin [4]

Answer:

$80^{\circ} C$

Step-by-step explanation:

You are making rusks and have to dry them overnight at a temperature of 176° F.

The given temperature is in Fahrenheit. We need to convert it into °C.

The relation between Fahrenheit and °C is given by :

$C=\dfrac{5}{9}(F-32)$

Put F = 176

So,

$C=\dfrac{5}{9}(176-32)\\\\C=\dfrac{5}{9}\times 144\\\\C=80^{\circ} C$

So, the temperature is equal to $80^{\circ} C$ .

3 0

2 years ago

$22.40 is the price you pay the discount is 30% what is the original amount?

Dmitriy789 [7]

30% of 22.40 is 6.72. 6.72 plus 22.40 is 29.12. Therefore the answer is 29.12.

4 0

2 years ago

What is the answer to this?

julia-pushkina [17]

Answer:

I think n = 7

Step-by-step explanation:

I might be wrong but I looked carefully and I think n is 7.

6 0

2 years ago

Read 2 more answers

Suppose r⃗ (t)=cos(πt)i+sin(πt)j+5tkr→(t)=cos(πt)i+sin(πt)j+5tk represents the position of a particle on a helix, where zz is th

gtnhenbr [62]

Answer:

a) t = 4

b) v = pi j + 5 k

c) rt = 1i + (pi t) j + (20 +5t )k

Step-by-step explanation:

You have the following vector equation for the position of a particle:

$r(t)=cos(\pi t)\hat{i}+sin(\pi t)\hat{j}+5t\hat{k}$ (1)

(a) The height of the helix is given by the value of the third component of the position vector r, that is, the z-component.

For a height of 20 you have:

$5t=20\\\\t=\frac{20}{5}=4$

(b) The velocity of the particle is the derivative, in time, of the vector position:

$v(t)=\frac{dr(t)}{dt}=-\pi sin(\pi t)\hat{i}+\pi cos(\pi t)\hat{j}+5\hat{k}$ (2)

and for t=4 (height = 20):

$v(t=4)=-\pi sin(\pi (4))\hat{i}+\pi cos(\pi (4))\hat{j}+5\hat{k}\\\\v(t=4)=-0\hat{i}+\pi\hat{j}+5\hat{k}$

(c) The vector parametric equation of the tangent line is given by:

$r_t(t)=r_o+vt$ (3)

ro: position of the particle for t=4

$r_o=cos(\pi (4))\hat{i}+sin(\pi (4))\hat{j}+20\hat{k}\\\\r_o=\hat{i}+0\hat{j}+20\hat{k}$

Then you replace ro and v in the equation (3):

$r_t=(1\hat{i}+20\hat{k})+(\pi \hat{j}+5\hat{k})t\\\\r_t=1\hat{i}+\pi t \hat{j}+(20+5t)\hat{k}$

3 0

3 years ago

Help me plzz I really need itttt​

Help me plzz I really need itttt