![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for

is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of

is always positive for

. That means at

there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function

is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
see explanation
Step-by-step explanation:
Calculate the distance (d) using the distance formula
d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 1,4) and (x₂, y₂ ) = (- 5, 3)
d = 
= 
=
=
≈4.12 ( to 2 dec. places )
To find the midpoint use the midpoint formula
[0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]
Using the same points as above then
midpoint = [0.5(- 1- 5), 0.5(4 + 3 ) ] = [0.5(- 6), 0.5(7) ] = (- 3, 3.5 )
Answer:
Ishaan is 49 years old.
Step-by-step explanation:
Let the present age of Christopher be 'C'.
Let the present age of Ishaan be 'I'.
From the given data, we can form equations which will help us solve the problem.
Christopher is 20 years younger than Ishaan. This means:
C = I - 20 . . . (1)
Fourteen years ago, Ishaan would have been (I -14) years old and Christopher (C - 14) years old.
From the data, I - 14 = 3(C - 14) . . . (2)
Substituting the value of C in Equation 2, we get:
I - 14 = 3(I - 20 - 14)
⇒ I - 14 = 3(I - 34)
⇒ I - 14 = 3I - 112
⇒ 2I = 112 + 14 = 98
⇒ I = 49
So, Ishaan is 49 years old.
Area of a circle is π*r²
sub what we're given
49π= πr²
49π= π*r²
r²= 49π/π
r²=49
r=7
The diameter is twice the radius therefore the diameter is 14 units